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## Homework Statement

The International Space Station (ISS) circles the Earth at an altitude of 347 km.

What is the period of the orbit of the ISS expressed in minutes?

G=6.67x10^-11 N * m^2 /kg^2

M(Earth)=5.98*10^24 kg

## Homework Equations

T^2/R^3 = (4Pi^2)/(GM)

So: T^2= Sqrt(((4Pi^2)/(GM))*(r^3))

## The Attempt at a Solution

Alright, so I've been plugging in these numbers for awhile, and I keep getting the wrong answer: 1.1 seconds. The right answer is 91.3 min.

T is in seconds when initially calculated, right? I'm still doing something wrong, but I'm hoping to just double check on that.