What is the physical dimension/unit of Probability current?

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Homework Help Overview

The discussion revolves around determining the physical dimension of probability current in the context of quantum mechanics, specifically for a particle in one dimension. Participants explore the relationship between the wave function and probability, as well as the implications of various mathematical expressions related to probability current.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to analyze the dimensions of the wave function and its derivatives, questioning whether the wave function is dimensionless or has a specific dimension. There is exploration of the relationship between probability density and the probability current density.

Discussion Status

The discussion is active, with participants providing insights and questioning each other's assumptions about the dimensions involved. Some suggest that the wave function might be dimensionless, while others propose that it has dimensions related to probability density. There is no explicit consensus on the final dimension of the probability current.

Contextual Notes

Participants note the importance of dimensional analysis in quantum mechanics and the potential confusion arising from different interpretations of the wave function's dimensions. The discussion also reflects on the constraints of working within a one-dimensional framework.

EhrEnFeest
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Homework Statement


Question:
What is the physical dimension of Probability Current for a particle in 1 dimension? (Quantum Mechanics)

Homework Equations


Quantum mechanical Probability Current:
07e268a6edab33f979b674b6b05b6d08.png


The Attempt at a Solution


I know the physical dimension of mass, that is kg. If I know every dimension, I can try some things and I can find the dimension of the observable. But now, I'm stuck. I guess that the wave function has no dimension, because it is very related to probability. But what's the case with $$ \frac{\partial \Psi}{\partial x} $$?
 
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Hello Feest, :welcome:

m-1 I would dare to venture ... (on your last question)
 
BvU said:
Hello Feest, :welcome:

m-1 I would dare to venture ... (on your last question)
But h has dimension of action. Taking Ψ to be dimensionless, j would appear to have dimension of velocity.
 
Actually ##j## is a probability current density.
 
BvU said:
Actually ##j## is a probability current density.
Just realized you meant m as metres, not mass. The question is for dimension, so I would answer L-1 there.
But what do you think the dimension of j is, if not LT-1?
 
With $${\partial \rho\over \partial t} + \nabla\cdot {\bf j} = 0
$$ where ##\rho = \psi^*\psi ## and ##\int \rho \, d\tau = 1##, I would end up with L-2T-1 :smile:

[edit] And now I have to backtrack to 1 dimension as cleary stated in post #1 (o:)) ending up with T-1 :smile:
 
EhrEnFeest said:
I guess that the wave function has no dimension, because it is very related to probability.
So here we must react also: It is related to probability in the sense that $$\int \psi^*\psi\,d\tau = 1 $$where the integral is over all space. The ##1## is dimensionless: a genuine probability. So guess again !
 
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BvU said:
So here we must react also: It is related to probability in the sense that $$\int \psi^*\psi\,d\tau = 1 $$where the integral is over all space. The ##1## is dimensionless: a genuine probability. So guess again !

This is a nice question to answer. It took me some time but I think:
∫ψ∗ψdτ=1 has no dimensions.
But as you integrate over space, and in this case this is one-dimensional, the dimension of ψ∗ψ is multiplied with [length]. And then ψ has a dimension of [(1/length)^½]?
 
An unavoidable conclusion, isn't it ? I never worried about the wave function having a dimension (always considered it as dimensionless) and would have liked to keep it that way. But -- unless we are being corrected -- this is what comes out !
 
  • #10
So thank you everyone!

Conclusion: the dimension of the probability current is [1/time]?

These physical dimensions used to help me give interpretations to different physical quantities. But in QM, that's not (yet) the case. :)
 

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