What is the Polynomial P(x) Given a Specific Quotient and Remainder?

  • Context: MHB 
  • Thread starter Thread starter missnerdist
  • Start date Start date
  • Tags Tags
    Polynomial
Click For Summary
SUMMARY

The polynomial P(x) can be determined using the division algorithm for polynomials. Given that P(x) is divided by (2x + 1) with a quotient of (x^2 - x + 2) and a remainder of 5, the formula P(x) = (2x + 1)(x^2 - x + 2) + 5 can be applied. After performing the multiplication and simplification, P(x) is found to be 2x^3 - x^2 + 4x + 7. This method effectively utilizes the relationship between the divisor, quotient, and remainder to reconstruct the original polynomial.

PREREQUISITES
  • Understanding polynomial division
  • Familiarity with the division algorithm for polynomials
  • Basic algebraic manipulation skills
  • Knowledge of polynomial expressions and their properties
NEXT STEPS
  • Study polynomial long division techniques
  • Learn about the Remainder Theorem and its applications
  • Explore synthetic division for polynomials
  • Investigate polynomial interpolation methods
USEFUL FOR

Students in algebra, mathematics educators, and anyone interested in polynomial functions and their properties will benefit from this discussion.

missnerdist
Messages
6
Reaction score
0
I can't seem to figure this out.

When a polynomial P(x) is divided by (2x+1) the quotient is x^2-x+2 and the remainder is 5. What is P(x)?
 
Mathematics news on Phys.org
A hint: When 7 is divided by 3 the quotient is 2 and the remainder is 1.
 
If P divided by A has quotient Q with remainder R, P/A= Q+ R/A, then P= AQ+ R. You are told what A, Q, and R are. Just do the algebra to find P.
 

Similar threads

  • · Replies 48 ·
2
Replies
48
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K