What is the Power Output and Efficiency of a Coal-Burning Power Plant?

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SUMMARY

The discussion focuses on calculating the heat discarded and the heat supplied by a coal-burning power plant with a power output of 491 MW and a thermal efficiency of 39.0%. The relevant equation for efficiency, η = W/Qh, is highlighted, where W represents the power output and Qh is the heat supplied. Participants express confusion over applying thermodynamic principles to derive the required values, indicating a need for clarity on the definitions and calculations involved.

PREREQUISITES
  • Understanding of thermal efficiency in power plants
  • Familiarity with the equation η = W/Qh
  • Basic knowledge of thermodynamics and energy conversion
  • Ability to perform calculations involving power and heat transfer
NEXT STEPS
  • Calculate heat discarded using the formula Qc = Qh - W
  • Research the concept of thermal efficiency in coal-burning power plants
  • Learn about energy conversion rates in thermodynamic systems
  • Explore the implications of efficiency on environmental impact and energy policy
USEFUL FOR

Students studying thermodynamics, engineers involved in power generation, and professionals interested in energy efficiency and environmental impact of coal-burning power plants.

planke
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Homework Statement



At a coal-burning power plant a steam turbine is operated with a power output of 491 MW. The thermal efficiency of the power plant is 39.0%.
(a) At what rate is heat discarded to the environment by this power plant?
______ GW

(b) At what rate must heat be supplied to the power plant by burning coal?
______ GW



Homework Equations


e = W/Qh = Qh-Qc / Qh


The Attempt at a Solution


I don't know how to approach this problem. Is there some equation for power to use for thermodynamics?

Thanks!
 
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planke said:

The Attempt at a Solution


I don't know how to approach this problem. Is there some equation for power to use for thermodynamics?

Thanks!

Start with the definition of efficiency η.

Remember power is nothing but the rate of change of energy. (1 W = 1 J/s)
 
I think this problem should be really straightforward, but I am still having trouble understanding how to solve it.
 
planke said:
I think this problem should be really straightforward, but I am still having trouble understanding how to solve it.

In your relevant equations you posted

e=W/Qh

So what is Qh ?
 

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