What is the Power Output and Efficiency of a Coal-Burning Power Plant?

Click For Summary

Homework Help Overview

The discussion revolves around a coal-burning power plant, specifically focusing on calculating the rate of heat discarded to the environment and the rate of heat supplied by burning coal, given the power output and thermal efficiency of the plant.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express uncertainty about how to approach the problem and whether there are specific equations applicable to thermodynamics. Some mention starting with the definition of efficiency and relate power to energy change.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the relevant equations and the meaning of variables such as Qh. There is no explicit consensus yet, but some guidance on definitions and relationships has been offered.

Contextual Notes

Participants are grappling with the definitions and equations related to thermal efficiency and power output, indicating a need for further exploration of these concepts.

planke
Messages
5
Reaction score
0

Homework Statement



At a coal-burning power plant a steam turbine is operated with a power output of 491 MW. The thermal efficiency of the power plant is 39.0%.
(a) At what rate is heat discarded to the environment by this power plant?
______ GW

(b) At what rate must heat be supplied to the power plant by burning coal?
______ GW



Homework Equations


e = W/Qh = Qh-Qc / Qh


The Attempt at a Solution


I don't know how to approach this problem. Is there some equation for power to use for thermodynamics?

Thanks!
 
Physics news on Phys.org
planke said:

The Attempt at a Solution


I don't know how to approach this problem. Is there some equation for power to use for thermodynamics?

Thanks!

Start with the definition of efficiency η.

Remember power is nothing but the rate of change of energy. (1 W = 1 J/s)
 
I think this problem should be really straightforward, but I am still having trouble understanding how to solve it.
 
planke said:
I think this problem should be really straightforward, but I am still having trouble understanding how to solve it.

In your relevant equations you posted

e=W/Qh

So what is Qh ?
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
18
Views
9K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 23 ·
Replies
23
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K