MHB What is the probability density for a given exponential functional integral?

Click For Summary
The discussion focuses on determining the probability density of the integral $$\int_0^t h(s) e^{2\beta(\mu(s) + W_s)}$$ where $\beta > 0$, and $h, \mu$ are continuous functions with $h \geq 0$, while $W$ represents standard Brownian motion. The original poster seeks clarification on the term "law," which refers to the probability density of this integral. They reference a known case where $\mu(s) = -\nu s$ and $h(s) = 1$, citing a result from Marc Yor's book on exponential functionals of Brownian motion. The thread emphasizes the need for further insights into the probability density for the general case presented.
gnob
Messages
11
Reaction score
0
Good day!
I have a question regarding the law of the ff:
$$
\int_0^t h(s) e^{2\beta(\mu(s) + W_s)}
$$
where $\beta >0;$ $h,\mu$ are continuous functions on $\mathbb{R}_+$ with $h\geq 0;$
and $W=\{W_s,s\geq 0\}$ is a standard Brownian motion.

Thanks for any help.:D
 
Physics news on Phys.org
gnob said:
Good day!
I have a question regarding the law of the ff:
$$
\int_0^t h(s) e^{2\beta(\mu(s) + W_s)}
$$
where $\beta >0;$ $h,\mu$ are continuous functions on $\mathbb{R}_+$ with $h\geq 0;$
and $W=\{W_s,s\geq 0\}$ is a standard Brownian motion.

Thanks for any help.:D

Please, can You better explain what is the question You have?...

Kind regards

$\chi$ $\sigma$
 
gnob said:
Good day!
I have a question regarding the law of the ff:
$$
\int_0^t h(s) e^{2\beta(\mu(s) + W_s)}
$$
where $\beta >0;$ $h,\mu$ are continuous functions on $\mathbb{R}_+$ with $h\geq 0;$
and $W=\{W_s,s\geq 0\}$ is a standard Brownian motion.

Thanks for any help.:D

Many thanks for the reply. What I meant of "law" is the probability density of the given integral. For the case $\mu(s) = -\nu s$ where $\nu$ is a positive constant and $h(s)=1,$ the law was already known (Corollary 1.2, p95) from Mar Yor's book given here Exponential Functionals of Brownian Motion and Related Processes - Marc Yor - Google Books .

Thanks again for any insights. :D
 
First trick I learned this one a long time ago and have used it to entertain and amuse young kids. Ask your friend to write down a three-digit number without showing it to you. Then ask him or her to rearrange the digits to form a new three-digit number. After that, write whichever is the larger number above the other number, and then subtract the smaller from the larger, making sure that you don't see any of the numbers. Then ask the young "victim" to tell you any two of the digits of the...

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
46
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K