What is the Probability of Error in an Adaptive Modulation System?

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SUMMARY

The discussion focuses on calculating the probability of error in an adaptive modulation system using specific modulation schemes: PQPSK, P16QAM, and P64QAM. The values derived are PQPSK = 0.502368, P16QAM = 0.0526855, and P64QAM = 0.000004, with a noise probability Pno = 0.4450. The calculations involve converting values from dB and utilizing the integral formula -exp(gamma/gamma_bar) evaluated from a to b, leading to results of 0.413505, 0.402453, and 0.0293970 for different parameters.

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Homework Statement


upload_2015-3-19_19-15-1.png


2. Homework Equations

upload_2015-3-19_19-13-57.png

The Attempt at a Solution



I can't figure out how to get those numbers, I think I have to convert from dB when actually calculating it but I'm unable to get those ones.

I have
PQPSK = 0.502368
P16QAM = 0.0526855
P64QAM = 0.000004
Pno = 0.4450
 
I figured it out,
upload_2015-3-26_18-26-20.png

Those are not in dB, even though I thought they were. So I was converting everything from dB or nothing from dB

so the integral ends up being -exp(gamma/gamma_bar) evaluated from a to b.

-exp(-52.98/ ( 10^(18/10) )) + exp(-10.6/ ( 10^(18/10) )) = 0.413505

-exp(-222.53/ ( 10^(18/10) )) + exp(-52.98/ ( 10^(18/10) )) = 0.402453

+ exp(-222.53/ ( 10^(18/10) )) = 0.0293970
 
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