What is the Proof of the Euler Lagrange Equation?

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ercagpince
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[SOLVED] Euler Lagrange Equation

Hi there ,
I am missing a crucial point on the proof of Euler Lagrange equation , here is my question :
[tex]\frac{\partial f}{\partial y}-\frac{d}{dx}\left(\frac{df}{dy^{'}}\right)=0[/tex] (Euler-Lagrange equation)

If the function "f" doesn't depend on x explicitly but implicitly and if y satisfies the Euler-Lagrange equation then ;
[tex]\frac{\partial f}{\partial x}=0[/tex]

Why is that so ? While ,supposedly , f is dependent to 3 variables : x,y,y' how van that statement be true ?
 
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If the function [tex]f[/tex] doesn't depend on x explicitly then

[tex]\frac{\partial f}{\partial x}=0[/tex]

and this has nothing to do with the

...and if y satisfies the Euler-Lagrange equation...

I don't understand what is the question :confused:
 
Still , the function f does depend on x through y and y' . That is why I asked basically .
 
That's why we use partial differention. Let

[tex]f\left(x,y(x),y'(x)\right)=x^2\,e^{y(x)}\,\ln{y'(x)}+\sin\left(x\,y(x)\right)[/tex]

then [itex]\frac{\partial\,f}{\partial\,x}[/itex] means

[tex]\frac{\partial\,f}{\partial\,x}=2\,x\,e^{y(x)}\,\ln{y'(x)}+y(x)\,\cos\left(x\,y(x)\right)[/tex]

i.e. you treat [tex]x,y(x),y'(x)[/tex] as independent variables.
 
Thanks for helping out!