What Is the Pulse Delay Time for a 20-Foot Coax Cable?

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SUMMARY

The pulse delay time for a 20-foot coax cable can be calculated using the relationship between speed, distance, and time. Electrical pulses travel at approximately 2/3 the speed of light (c) in standard BNC coax cables. For a 20-foot cable, the pulse delay time is determined by the formula time = distance/speed. Therefore, using the speed of 2/3 c, the pulse delay time can be accurately calculated.

PREREQUISITES
  • Understanding of the speed of light (c)
  • Familiarity with the concept of electrical signal propagation in coaxial cables
  • Basic knowledge of the formula for speed, distance, and time
  • Knowledge of BNC coax cable specifications
NEXT STEPS
  • Calculate pulse delay time for different lengths of coax cables
  • Research the speed of electrical signals in various types of coax cables
  • Explore the impact of cable quality on signal speed
  • Learn about signal integrity and its relation to pulse delay in coaxial systems
USEFUL FOR

Electrical engineers, telecommunications professionals, and students studying signal transmission in coaxial cables will benefit from this discussion.

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Homework Statement



Electrical pulses travel at about half of light speed through coax cables. Determine the pulse delay time for a cable with a length of 20 feet.



Homework Equations





The Attempt at a Solution



I don't think this question is very hard, but I can't find any relevant information in my notes, and our book is just a lab manual. Thanks in advance.
 
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How are speed, distance traveled, and time related? (Don't think too hard about this.)
 
Well speed=distance/time. I could use the speed and distance to find the time. Is that all "pulse delay time" refers to?
 
Yes, that is all there is to it. :smile:

BTW, I have found that electric signals travel about 2/3 c along standard BNC coax cables. But of course, you should use the speed given in the problem statement.
 
Wow. Ok, thanks a lot.
 

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