What is the Q-value of the Deuterium (d,p) Reaction?

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SUMMARY

The Q-value of the deuterium (d,p) reaction is calculated using the binding energy of deuterium and the neutron captured by the target. The binding energy of the deuteron is established at E=2.225 MeV, while the mass of the deuteron is noted as 1875.628 MeV. The equation Q = E(reactants) - E(products) is applied to derive the relationship between the masses involved. Clarification on the roles of deuterium and proton in the reaction is necessary for accurate calculations.

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  • Understanding of nuclear binding energy concepts
  • Familiarity with the deuterium (d) and proton (p) reaction
  • Knowledge of mass-energy equivalence principles
  • Proficiency in using the Q-value equation in nuclear reactions
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Homework Statement


Express the energy (Or heat of the reaction Q) of the reaction (d,p) as a function of the binding energy of deuterium and the binding energy of the neutron captured by the target.


Homework Equations



Bn / A ≈ 8 MeV

Bn = Binding energy, A = Atomic Number

Q = E(reactants) - E(products)



The Attempt at a Solution



This problem is translated form a french paper hence the lack of clarity,
basically our attempts involved finding the Binding energy of deuteron is E=2.225MeV, and the mass of deuteron is 1875.628MeV.


This means that m(d)-m(p)-m(n)=2.225MeV.

and that's where I am stuck?

Thanks in advance
 
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Is deuterium the target or is it the product? Your question is leaving out some details. Also what is 'd' and 'p'? It is also best if you write out the whole chemical formula.
 
See this is on a french physics handout which has me bewildered as I'm not a chemist, but a little cross discipline never hurt.

I think the d,p refers to deuterium proton which decays to a neutron. I think i'll go see my Professor and ask exactly what he's asking and post it up as I can't seem to find this example or solution anywhere, so it may be of useful reference to someone in the future.

Could just be shoddy translation on my part. I suspect.

Thanks
 

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