1. The problem statement, all variables and given/known data Calculate the total kinetic energy of the products of the reaction d+C-13 --> N-14 + n if the incoming deuteron (d) has 36.3 MeV. 2. Relevant equations Q=(Parent Mass - Daughter Mass - Decay Particle Mass)*c^2 1u = 931.5 MeV C-13 = 13.00335u N-14 = 14.003241u Neutron = 1.008664u deuteron = 2.014101 KE before = KE after 3. The attempt at a solution Alright I'm kinda lost on this problem though I feel it's easy. Since KE before=KE after I took the energy of the deuteron (36.3 MeV) and added that to the resting energy of C-13, which I got to be 13.00335*931.5= 12112.6MeV Now I thought that would be the answer, but it wasn't, so I tried subtracting the mass of the products from the mass of the reactants to get the Q value. So I took (2.014101+13.00335)-(14.003241+1.008664)=.005546u*931.5MeV/c^2= 5.1661MeV, ...but that wasn't right either so I'm confused as to what I'm actually trying to find. If someone could tell me what I'm solving for and what equation to use? Or if I have a wrong conversion factor or isotope mass? Thanks!