Kinetic Energy of the Products of Nuclear Reaction?

In summary, the total kinetic energy of the products of the reaction d+C-13 --> N-14 + n can be calculated by finding the Q value (difference in mass between the reactants and products) and adding it to the incoming deuteron's kinetic energy. It is important to note that the Q value must be calculated correctly, and the neutron's rest mass should not be included in the calculation.
  • #1
JayRemmy
4
0

Homework Statement


Calculate the total kinetic energy of the products of the reaction d+C-13 --> N-14 + n if the incoming deuteron (d) has 36.3 MeV.


Homework Equations


Q=(Parent Mass - Daughter Mass - Decay Particle Mass)*c^2
1u = 931.5 MeV
C-13 = 13.00335u
N-14 = 14.003241u
Neutron = 1.008664u
deuteron = 2.014101
KE before = KE after

The Attempt at a Solution


Alright I'm kinda lost on this problem though I feel it's easy. Since KE before=KE after I took the energy of the deuteron (36.3 MeV) and added that to the resting energy of C-13, which I got to be 13.00335*931.5= 12112.6MeV
Now I thought that would be the answer, but it wasn't, so I tried subtracting the mass of the products from the mass of the reactants to get the Q value. So I took (2.014101+13.00335)-(14.003241+1.008664)=.005546u*931.5MeV/c^2= 5.1661MeV,

...but that wasn't right either so I'm confused as to what I'm actually trying to find. If someone could tell me what I'm solving for and what equation to use? Or if I have a wrong conversion factor or isotope mass? Thanks!
 
Physics news on Phys.org
  • #2
No, total energy before equals total energy after (not just kinetic). Momentum before equals momentum after, however.
 
  • #3
I understand but can I find momentum for C-13 if there is no velocity? The only thing I can think of is to do KE=p^2/2m, but that doesn't give me the right answer either. I ended up getting 10261.7 MeV.
 
  • #4
You shouldn't need momentum since you have the rest mass energies of the reactants, the KE of the deuteron (the others are assumed to be at rest from the problem description), and the rest masses of the products.
 
  • #5
Ok, so I took;

36.3+(13.00335*931.5) = 12148.9 MeV and
(14.003241*931.5)+(1.008664*931.5)= 13983.6 and
12148.9-133983= 1834.67 (wrong answer)

so I tired taking out the neutron rest mass because I assume it's moving afterwards...
through the same process I got 895.098 (wrong answer).

Am I going through the correct process to get the resting KE?
 
  • #6
Ahh, I just got the right answer, I took
(13.00335+2.0141)-(14.003241+1.008664) = .005546 and
.00546* 931.5 = 5.1661 and
5.1661+36.3 = 41.46, which was the correct answer.

So for a problem like this I just take the Q value, then add that to the incoming KE value?
 

1. What is kinetic energy?

Kinetic energy is the energy an object possesses due to its motion. It is a scalar quantity and is measured in joules (J).

2. How is kinetic energy related to nuclear reactions?

Nuclear reactions involve the conversion of mass into energy. The kinetic energy of the products of a nuclear reaction is a result of this conversion and is typically much greater than the kinetic energy of the reactants.

3. How is the kinetic energy of the products of a nuclear reaction calculated?

The kinetic energy of the products can be calculated using the equation E=mc², where E is the energy, m is the mass of the products, and c is the speed of light.

4. How does the amount of kinetic energy produced in a nuclear reaction compare to other forms of energy?

The amount of kinetic energy produced in a nuclear reaction is significantly greater than the energy produced in chemical reactions. It is also more concentrated and can be harnessed to generate electricity or power weapons.

5. What factors can affect the kinetic energy of the products of a nuclear reaction?

The amount of kinetic energy produced in a nuclear reaction can be affected by factors such as the type of nuclear reaction, the mass of the reactants, and the speed at which the products are ejected from the reaction. It can also be affected by any energy lost through radiation or other forms of energy during the reaction.

Similar threads

  • Advanced Physics Homework Help
Replies
6
Views
1K
  • Advanced Physics Homework Help
Replies
2
Views
2K
  • High Energy, Nuclear, Particle Physics
Replies
14
Views
1K
  • Advanced Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
3
Views
525
  • High Energy, Nuclear, Particle Physics
Replies
5
Views
630
  • Introductory Physics Homework Help
2
Replies
54
Views
8K
  • High Energy, Nuclear, Particle Physics
Replies
2
Views
2K
Replies
5
Views
916
  • Mechanics
Replies
3
Views
70
Back
Top