What is the Relationship Between Intensity and Wattage?

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SUMMARY

The relationship between intensity and wattage in sound amplification is logarithmic. To achieve a sound output that is twice as loud as a 20 W amplifier, a power of 80 W is required, while a fourfold increase in loudness necessitates a 320 W amplifier. This is based on the principle that doubling the amplitude results in quadrupling the intensity, which is measured in decibels (dB).

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  • Understanding of logarithmic relationships in physics
  • Knowledge of sound intensity and amplitude
  • Familiarity with decibel (dB) measurements
  • Basic principles of audio amplification
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  • Research the decibel scale and its application in sound intensity
  • Explore the principles of audio amplifier design
  • Learn about the relationship between amplitude and intensity in sound waves
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Audio engineers, sound technicians, students studying acoustics, and anyone interested in understanding sound amplification and intensity relationships.

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Homework Statement


OK, so this is a very basic question but i am uncertain what the relationship is. I know its logarithmic, but i don't know how to draw a conclusion. Here is the question:
If you want an amplifier which will give a sound output which is twice as lod as your present 20 W amplifier, what amplifier power should you buy? What if you wanted a sound output four times as loud?


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The Attempt at a Solution


I know that the relationship between Intensity and Wattage is logarithmic, but how do i draw a numeric conclusion?
 
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Are they looking for loudness or intensity?

The wattage of the amplifier is the maximum power it can supply to the signal.
The intensity a wave is the square of it's amplitude.
I suspect you are thinking of decibels.

If you double the amplitude, you get four times the intensity.
 

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