What is the Relationship Between Voltage and Capacitors in a Series Circuit?

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Homework Help Overview

The discussion revolves around the relationship between voltage and capacitors in a series circuit, particularly focusing on a problem from an AP Physics C E&M exam. Participants are exploring the behavior of voltage across a capacitor when connected in series with a resistor during the charging process.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning why the voltage across the capacitor is equal to the source voltage when a resistor is present in series. There is an exploration of the charging behavior of the capacitor and its implications on voltage distribution.

Discussion Status

The discussion is active, with participants providing insights into the charging process of the capacitor and referencing the time constant in relation to reaching steady state. There is acknowledgment of the mathematical relationship between charge and voltage, though some confusion remains regarding its implications at different time intervals.

Contextual Notes

Participants are referencing specific equations and conditions related to capacitor charging, including the time constant and steady state conditions. There is an emphasis on the assumption that steady state is reached after a certain time period, which may not be universally applicable without further clarification.

kd2amc
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Homework Statement


I was going through this PDF on my own to review for my AP Physics C E&M exam: https://apcentral.collegeboard.org/...course=ap-physics-c-electricity-and-magnetism

I was also watching this video (which discusses the solutions):

The part I am stuck on is part 2(a) (it is hard for me to copy and paste the contents of the PDF into here).

(The solution to part 2(a) is at about 16 minutes into the video).

Homework Equations


Q=CV

The Attempt at a Solution


Why is voltage across C0 equal to V0? I understand how this be the case if the resistor R1 was not there (since voltages are the same for components connected in parallel); however, since the resistor is connected to the capacitor in series, I thought that the voltage V0 would be split across C0 and R1 (which means C0 would have a voltage less than V0). Why is this not the case?

Thank you so much for any help!
 
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kd2amc said:
I thought that the voltage V0 would be split across C0 and R1 (which means C0 would have a voltage less than V0).
Yes, that will be the case when the capacitor is 'charging' i.e. the charge on the capacitor will be increasing with time. You need to find the equation for charge as a function of time.
 
cnh1995 said:
Yes, that will be the case when the capacitor is 'charging' i.e. the charge on the capacitor will be increasing with time. You need to find the equation for charge as a function of time.

Thank you for your help. According to my notes, the charge as a function of time is Q = CV(1-e^-t/RC). I'm not sure how to use this equation to conclude that the voltage across C0 = V0, though. Doesn't this equation actually imply that Q = 0 at time t=0?
 
kd2amc said:
Doesn't this equation actually imply that Q = 0 at time t=0?
Right.
kd2amc said:
that the voltage across C0 = V0
You get this condition at t=∞(mathematically) and that represents the steady state. In steady state, the current through the capacitor is zero, meaning that it is fully charged.

Practically, you don't need infinite time to reach steady state. It is assumed that the steady state is reached at t=5RC (or 6RC)(where RC is the time constant) since the capacitor will have more than 99% of its steady state voltage by that time.
 
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Oh! I see now! Thank you!
 
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