What is the relativistic equation for finding kinetic energy?

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Discussion Overview

The discussion revolves around the relativistic equation for calculating kinetic energy, particularly for objects moving at significant fractions of the speed of light, such as a ball traveling at 99% the speed of light. The conversation also touches on whether photons possess kinetic energy.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant asks for the equation to calculate the kinetic energy of a ball moving at relativistic speeds and inquires about the kinetic energy of photons.
  • Another participant provides the formula for kinetic energy as \(E_{\text{kin}} = (\gamma - 1)mc^2\), where \(\gamma = \frac{1}{\sqrt{1 - \frac{v^2}{c^2}}}\), and mentions the energy of a photon as \(E_{\text{photon}} = hf\).
  • A different participant reiterates the kinetic energy formula and expresses uncertainty about the treatment of photons.
  • One participant argues that photons, being massless, do not have rest energy, implying that all their energy is kinetic, and contrasts this with massive particles that have a minimum energy due to rest mass.
  • Another participant supports the idea that photons have no rest energy and all energy is kinetic, while also acknowledging their uncertainty in the discussion.
  • A later reply introduces the relativistic energy-momentum relation \(E^2 = (mc^2)^2 + p^2c^2\) and derives the kinetic energy from it, noting that for photons, the mass \(m=0\) leads to \(E_{\text{kin}} = pc\).

Areas of Agreement / Disagreement

Participants express differing views on the kinetic energy of photons, with some asserting that they possess kinetic energy while others argue against it due to their massless nature. The discussion remains unresolved regarding the treatment of photon energy.

Contextual Notes

Some participants express uncertainty about the implications of mass on energy calculations and the definitions of kinetic energy in different frames of reference.

Ralphonsicus
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Let's say, I wanted to find the kinetic energy of a ball traveling at 99% the speed of light, what is the equation used for that calculation?

And also, do photons have kinetic energy?

Thanks.
 
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Ralphonsicus said:
Let's say, I wanted to find the kinetic energy of a ball traveling at 99% the speed of light, what is the equation used for that calculation?

And also, do photons have kinetic energy?

Thanks.

The formula for a particle of mass m has a kinetic energy is given by [itex](\gamma - 1)mc^2[/itex] where [itex]\gamma = {{1}\over{\sqrt{1-{{v^2}\over{c^2}}}}}[/itex] where c is the speed of light.

The energy of a photon with frequency [itex]f[/itex] is [itex]E_{photon} = hf[/itex] where h is Planck's constant.
 
mc^2(γ - 1)

where γ = 1/(√(1- v^2/c^)
 
Ralphonsicus said:
Let's say, I wanted to find the kinetic energy of a ball traveling at 99% the speed of light, what is the equation used for that calculation?
Here you go :wink: http://bit.ly/xZN1YS
Ralphonsicus said:
And also, do photons have kinetic energy?
I don't think so because they are massless.
 
I missed the question about photons. What Pengwino says is correct, but (and we simul-posted, else I wouldn't have bothered) adding a little more, and disagreeing with Ryan_m_b:

Since a photon is massless it has no rest energy. Therefore all of its energy is kinetic. For a massive particle, you can say the frame dependent energy has a minimum - the rest energy; the frame dependent additional energy is kinetic. For a photon, there is no minimum - you can redshift to arbitrarily close to zero energy by choice of frame, consistent with its having no rest energy and all kinetic energy.
 
PAllen said:
disagreeing with Ryan_m_b...Since a photon is massless it has no rest energy. Therefore all of its energy is kinetic
I tried to make it clear I wasn't sure :smile: good to learn though, cheers.
 
The relativistic energy-momentum relation reads

[tex]E^2 = (mc^2)^2 + p^2c^2[/tex]

From this equation the kinetic energy can be determined directly

[tex]E_\text{kin} = E - mc^2 = \sqrt{(mc^2)^2 + p^2c^2} - mc^2[/tex]

For photons we have m=0 and therefore

[tex]E_\text{kin} = E = pc[/tex]

For m>0 one gets the equations with v<c mentioned above, of course
 

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