What is the Relevance of the Second Solution in a Quadratic Equation?

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SUMMARY

The discussion centers on solving a quadratic equation derived from a physics problem involving the fall of a boulder from a cliff. The hiker notes that the boulder takes 1.3 seconds to travel the last third of the fall, leading to the calculation of the cliff's height (H). The two solutions obtained from the quadratic equation are H1 = 214.9 m and H2 = 0.3136 m. The relevance of H2 is questioned, as it represents a non-physical solution in this context, indicating that only H1 is valid for the height of the cliff.

PREREQUISITES
  • Understanding of kinematic equations, specifically v² = v₀² + 2gX and X = v₀t + 0.5gt²
  • Knowledge of quadratic equations and their solutions
  • Familiarity with gravitational acceleration (g = 9.8 m/s²)
  • Basic calculator skills for solving quadratic equations
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  • Learn about the significance of the discriminant in determining the nature of quadratic solutions
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Homework Statement


An alert hiker sees a boulder fall from a cliff. He notes that it takes 1.3 sec for the boulder to travel the last third of the fall. a.)Find the height H of the cliff. B.) If you found a quadratic equation of two solutions for a.) what is the relevance of the other one

Homework Equations


v2=vo2+2gX
X=vot+0.5gt2

The Attempt at a Solution


v2=vo2+2gX ;vo=0;X=H/3
v2=2(9.8m/s2)(H/3)
v=sqrt(13.07m/s2H)

X=vot+0.5gt2
H/3=sqrt(13.07m/s2H)(1.3s)+8.281m
H=3.9ssqrt(13.07m/s2H)+8.281m
H-3.9ssqrt(13.07m/s2H)-8.281m=0
I just used my calculator to solve this quadratic equation
sqrt(H1)=14.66m0.5
H=214.9 which is the same with the book's answer
sqrt(H2)=-0.56m0.5
H2=0.3136m
I can't answer B.) What is the relevance of H2
Please reply,, Thanks!


 
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iampaul said:

Homework Statement


An alert hiker sees a boulder fall from a cliff. He notes that it takes 1.3 sec for the boulder to travel the last third of the fall. a.)Find the height H of the cliff. B.) If you found a quadratic equation of two solutions for a.) what is the relevance of the other one

Homework Equations


v2=vo2+2gX
X=vot+0.5gt2

The Attempt at a Solution


v2=vo2+2gX ;vo=0;X=H/3
v2=2(9.8m/s2)(H/3)
v=sqrt(13.07m/s2H)

X=vot+0.5gt2
H/3=sqrt(13.07m/s2H)(1.3s)+8.281m
H=3.9ssqrt(13.07m/s2H)+8.281m
H-3.9ssqrt(13.07m/s2H)-8.281m=0
I just used my calculator to solve this quadratic equation
sqrt(H1)=14.66m0.5
H=214.9 which is the same with the book's answer
sqrt(H2)=-0.56m0.5
H2=0.3136m
I can't answer B.) What is the relevance of H2
Please reply,, Thanks!


Firstly, were your answer(s) to the first part correct - I don't want to spend time proving you are correct/incorrect.
 

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