What is the result of mixing 10g of ice at -10 deg celcius?

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Mixing 10g of ice at -10 degrees Celsius with water will result in the ice absorbing heat until it reaches 0 degrees Celsius, where it will start melting. The specific heat capacity of ice is 2.1 J/g K, and the latent heat of fusion is 336 J/g, which will affect the total energy calculations. The discussion highlights the need for additional information, such as the amount and temperature of the water being mixed with the ice, to fully solve the problem. Without this data, the outcome remains incomplete. The final temperature of the mixture will stabilize at 0 degrees Celsius once the ice has melted.
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Homework Statement


Find the result of mixing 10g of ice at -10 deg celcius. Specific heat capacity of ice = 2.1 J/g K. Specific heat capacity of water is 4.2 J/g K. Specific latent heat of ice = 336 J/g.


Homework Equations





The Attempt at a Solution



0.625g, temperature will remain at 0 deg celcius.
 
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Your problem statement is incomplete. Mixing 10g of ice with what?
 
mixing with water
 
OK. How much water? Is this going to be a Twenty Questions session?
 
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