What is the result of the complex integral with Riemann zeta function?

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Discussion Overview

The discussion revolves around evaluating the complex integral involving the Riemann zeta function, specifically the integral of the form \(\int_{c-i\infty}^{c+i\infty}ds\zeta(s)(x^{s}/s)\). Participants explore the singularities of the integral and the implications for its evaluation.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents the integral and notes the presence of singularities at \(s=0\) and \(s=1\), questioning if there are additional singularities.
  • Another participant suggests that the integral can be evaluated using Perron's formula under the conditions \(c>1\) and \(x>0\), implying familiarity with the poles of the zeta function.
  • A participant claims to see two poles and proposes a result of the form \(A + Bx\), where \(A\) and \(B\) are real constants, expressing surprise that the integral does not yield a sum over the zeros of the Riemann zeta function.
  • Another participant challenges the method used to arrive at the proposed result, asking about the contour applied in the residue theorem and suggesting that the expectation of a sum over the zeros is misplaced based on Perron's formula.

Areas of Agreement / Disagreement

Participants express differing views on the evaluation of the integral and the expectations regarding the results, indicating that the discussion remains unresolved with multiple competing interpretations.

Contextual Notes

Participants reference the poles of the zeta function and the application of the residue theorem, but there are unresolved aspects regarding the choice of contour and the implications of Perron's formula.

eljose
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let be the integral..where [tex]\zeta(s)[/tex] is the Riemann zeta function.

[tex]\int_{c-i\infty}^{c+i\infty}ds\zeta(s)(x^{s}/s)[/tex]

then what would be the result?..there would be two singularities at the points s=0 and s=1 the problem is if there would be any other singularitiy on the integral
 
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This is a straightforward application of Perron's if c>1 and x>0. You surely know where the poles of zeta are by now, no?
 
well i see two poles inside the integral..so i would get the result:

[tex]A+Bx[/tex] (poles at s=0 and s=1 with A and B real constants) but it seems a very easy integral, i would expected a sum over the zeros of Riemann Zeta or something similar..uummm..perhaps i have made something wrong.
 
eljose said:
well i see two poles inside the integral..so i would get the result:

[tex]A+Bx[/tex] (poles at s=0 and s=1 with A and B real constants)

How did you get this? What contour did you try to apply the residue theorem to? If you want to say something about an unbounded contour you can't apply the residue theorem directly, you have to look at bounded contours and look at limits.

eljose said:
i would expected a sum over the zeros of Riemann Zeta or something similar..uummm..perhaps i have made something wrong.

You're seen perron's formula, look at it again closely. There's no way you should expect a sum over the zeros of zeta here.
 

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