What is the role of linear operators in quantum mechanics?

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SUMMARY

The discussion centers on the role of linear operators in quantum mechanics, specifically focusing on the linearity property defined by the equation Ô(α f1 + β f2) = α(Ô f1) + β(Ô f2). The operators discussed include Ô1 = d/dx and Ô2 = 3 d/dx + 3x². The participants analyze the application of these operators on functions g(x, t) = 3 d/dx + 3x² and h(x, t) = α sin(kx − ωt), with a specific focus on deriving the results of these operations. The final result for Ô2 g(x,t) is confirmed as 18xt³ + 9x⁴t³, emphasizing the independence of the outcome from time variable t.

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Students in quantum mechanics, particularly those in undergraduate programs, as well as educators and anyone seeking to deepen their understanding of linear operators and their applications in quantum physics.

Roodles01
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Homework Statement


Just starting third level Uni. stuff & am faced with linear operators from Quantum Mechanics & need a little help.
OK, an operator, Ô, is said to be linear if it satisfies the equation
Ô(α f1 + β f2) = α(Ô f1) + β(Ô f2)
Fine

but I have an equation I can't wrap my head around, maybe just rusty, a hint would be nice, though.



Homework Equations


Ô1 = d/dx;
Ô2 =3 d/dx +3x^2;

 
Find the new functions obtained by acting with each of these operators on
(a) g(x, t) =3 d/dx +3x^2
(b) h(x, t)=α sin(kx − ωt).



The Attempt at a Solution


Now
Ô1 g(x,t) = 6xt^3
But not sure about how to get
Ô2 g(x,t) =

how to get this middle bit, please . . . . .

Answer is 18xt^3 + 9x^4 t^3
 
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You realize there's no 't' dependence in g(x,t), so that the outcome must be independent of t, right ? Actually the way you wrote it, g(x,t) is Ô2, not a wavefunction, but also an operator.
 
I went back to the question, scanned the problem in & looking again showed a huge error in seeing things.
What a twit.
 

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