What is the rotational kinetic energy?

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SUMMARY

The discussion centers on calculating the rotational kinetic energy of a uniform density rod with a mass of 1.2 kg and a length of 0.7 m, rotating at an angular speed of 50 rad/s. The relevant formula for rotational kinetic energy is K = 1/2 I * ω², where I is the moment of inertia. For a rod rotating about an axis perpendicular to its length, the moment of inertia is given by I = 1/12 ML². The participants clarify that for exam purposes, the radius can be considered negligible, simplifying the calculation.

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MillerGenuine
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Homework Statement



Uniform density rod with mass 1.2 kg, length 0.7m rotates around an axis perpendicular to the rod, with angular speed 50 rad/sec. its center moves with a speed of 8m/s.
What is the rotational kinetic energy?

Homework Equations



K= 1/2 I * V^2 (V is angular speed, 50 rad/s)

I_cylinder = 1/12 ML^2 + 1/4MR^2





The Attempt at a Solution




I can't seem to find my radius. I am assuming you find it by using the velocity of the center?
 
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Hi MillerGenuine! :smile:

(try using the X2 icon just above the Reply box :wink:)
MillerGenuine said:
I_cylinder = 1/12 ML^2 + 1/4MR^2

I can't seem to find my radius.

In exam questions, a rod (like a cable or a string) can be assumed to have zero radius …

just use 1/12 ML2 :biggrin:
 

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