What is the separation between the two surfaces

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SUMMARY

The separation between two equipotential surfaces in a uniform electric field of 13.3 x 10^3 N/C, where one surface is at 1543 V and the other at 951 V, can be calculated using the formula delta x = (delta V) / E. By substituting the values, delta x is determined to be 0.044 meters or 4.4 cm. This calculation confirms the relationship between electric field strength, potential difference, and distance between surfaces.

PREREQUISITES
  • Understanding of electric fields and equipotential surfaces
  • Familiarity with the equation Eave = - deltaV/delta x
  • Basic knowledge of voltage and potential difference
  • Ability to perform unit conversions (e.g., volts to meters)
NEXT STEPS
  • Study the concept of electric fields and their properties in detail
  • Learn about equipotential surfaces and their significance in electrostatics
  • Explore practical applications of electric fields in real-world scenarios
  • Investigate advanced topics such as Gauss's Law and its relation to electric fields
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators seeking to clarify concepts related to electric fields and potential differences.

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Homework Statement


You measure a uniform electric field of 13.3 x 10^3 N/C between two equipotential surfaces. One surface is at a potential of 1543 V and the other is at 951 V. What is the separation between the two surfaces?

Homework Equations


Eave = - deltaV/delta x


The Attempt at a Solution


After rewriting the equation I did delta x = (1543V-951V)/(13.3 x 10^3) N/C

I am not sure I am doing this right

Thanks for any help!
 
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