Originally posted by matt grime
hyper surface? do you even know what one of those is? And therefore it is an operation not on the topological space but.. well, assuming it even has a meaningful notion of hypersurface, then an operation on something of dimension 'one fewer' anyone got an inner product lying around? Or a ring of algebraic functions to help define this hyper surface?
Here is a topological space (with a metric)
R^n ; n>17
Define a multiplication on R^n which allows you to do this specious nonsense with Fermat's LAst theorem? Make sure that you have at least an integral domain. Field would be nice... Heck, even a division algebra would be a start.
Wow, defining a manifold structure on the set of all sets, you're a genius, my cap is doffed.
Let's definitely define, in accordance, with that which we have most excellently learned:
A topological space is a set X along with a happy family of subsets of X, called the open sets, requred to satisfy certain conditions, like the empty set and X itself are both open, if the subsets of X, U and V are open, so is the intersection of U and V, of course! And if the sets U_a of X are open, then so is the union of U_a. The collection of sets taken to be open is called the topology of X. An open set containing a point x, which is an element of X, is called a neighborhood of x. The complement of an open set is called "closed".
So with the use of topology it becomes possible to define continuous functions, and roughly speaking, a function is continuous if it sends nearby points to nearby points, of course. The conceptual notion of "nearby" can be made precise using open sets. Ergo a function f: X-->Y from one topological space to another is defined to be continuous because if we are given any open set U subset of Y, then the inverse image f^-1 U subset of X, is open. So the concept of manifold can be likened to that of a globe, whereby it may be covered with patches that look just like R^n.
A collection, U_a of open sets "covers" a topological space X if their union is all of X.
Well allrighty then, so, given topological spaces X and Y, there is a product X x Y, i.e. the product topology in which a set is open iff it is a union of sets of the form U x V, where U is open in X and V is open in Y .
If M is an m-dimensional manifold and N is an n-dimensional manifold, then M x N is an (m+n) dimensional manifold.
So simultanaety "S" is a spacelike hypersurface or "slice" through spacetime that cuts through event P, with a set of observers having worldlines crossing the simultanaety "simultaneously-orthogonally" having clocks that all read the same "proper" time at the instant of crossing.
The metric spaces are thus defined as being diffeomorphism invariant. Intersecting cotangent bundles[manifolds] are the set of all possible configurations of a system, i.e. they describe the phase space of the system. When the "wave-functions" intersect, and are "in phase", they are at "resonance", giving what is called the "wave-function collapse" of the Schrodinger equation.
Yes, is it possible to derive Einstein's field equation strictly in terms of quantum mechanical operators? using n-dimensional cross sections of cotangent vector spaces? Near a massive object M, the *isobar* cross sections increase in density as wavefunction density gradients, a possible solution? to Hartle and Hawking's "wavefunction of the universe"?
There is the Schrodinger equation: H(psi) = E(psi), where H is the Hamiltonian operator, the sum of potential and kinetic energies, and "psi" is the wavefunction. E is the energy of the system. The square of the wavefunction, is the probability of the position and momentum for the system.
The Wheeler DeWitt equation is the Schrodinger equation applied to the whole universe. Since the total energy of the universe is postulated to be zero[but is still not defined], the Wheeler DeWitt equation is: H(psi) = 0
There is a complementary path integral approach for this equation. The brilliant physicist Stephen Hawking, derived the wavefunction of the universe as a path integral, for a complex function of the classical configuration space:
psi(q) = integral exp(-S(g)/hbar) dg
The problem is that "dg" is not well defined either.
"exp" is the base of the natural logarithm "e" raised to a power.
The power in this case, is the quantity -S(g)/hbar, where S(g) is the Einstein Hilbert action. The Einstein Hilbert Action, is defined via the Lagrangian, which is the difference of kinetic and potential energies, and it has a formulation in general relativity:
Lagrangian = R vol
R is the Ricci scalar curvature of the metric g, derived by contracting the Ricci tensor and "vol" is the volume form associated to g.
The Einstein Hilbert action then becomes: S(g) = integral R vol
A topological group G, is a topological space such that the group multiplication ab = c is a continuous function from G x G into G and the operation inversion a^-1 = b is a continuous function from G into G, so one of the characteristic properties of a continuous function in a topological space, and if ab = c, with W being an open neighborhood of c, then there exist open neighborhoods U and V of a and b respectively, such that UV is a subset of W. UV is therefore defined as the set of all products a'b' where a' is an element of U and b' is an element of V.
Most definitely the standard operator T is bounded iff T transforms every point of the monad of the origin, 0, into a point in the monad of 0. Therefore a point is in the monad iff its norm is infinitesimal. The necessity of the condition is abundantly clear, and obviously so, because, T is bounded iff T transforms every point a in *B into a finite point.
||Ta|| =< ||T|| ||a||
If a is finite then Ta is also finite. Most definitely the standard operator T, is bounded iff T transforms every near standard point into a near standard point.
Hence a topological space is compact iff all points of *T are near standard.
Yes, a point is defined as "near standard" if there exists a standard point q such that p is an element of mu(q) , where mu(q) is the intersection of the set of open sets in T containing q.
The closed unit interval [0,1] is compact. But this finite unit is comprized of an infinite number of fractions... more later
Question:
Can light cone cross sections represent the operations of union and intersection analogously to Venn diagrams?