What is the solution for a matrix with a parameter in its determinant?

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SUMMARY

The discussion centers on finding the eigenvalues of the matrix M = [21, 7; 14, 7] by solving the determinant equation |(M - xI)| = 0. The user, Mr. Lard, derived the characteristic polynomial x² - 28x + 49 = 0 using the quadratic formula, resulting in eigenvalues of 14 ± 7√3. The solution method is confirmed as correct, with the term "parameters" clarified as eigenvalues in linear algebra terminology.

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lardycake
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Homework Statement


Hello all,

I have a parameter x of a matrix M = [21, 7
14, 7]
the determinant of
|(M - xI)| = 0

Homework Equations



I is known as the identity matrix

The Attempt at a Solution


My solution seems to be a bit far fetched:

(21 - x)(7-x) - 98 = 0

x2 - 28x + 147 - 98 = 0

x2 - 28x + 49 = 0

using the quadratic formula x = (28 +- root(28x28 - 4(1)(49))) / 2
which I got to be 14 +- 7root(3)

Is this the correct method and answer?

Regards,
Mr Lard
 
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Yes. And what you are calling parameters are usually called eigenvalues of the matrix.
 

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