What is the solution for log equations with a base of 4 and a difference of 3?

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The discussion centers on solving the logarithmic equation log4 x - log4 (x-3) = 5. Participants work through the steps, transforming the equation into log4 (x/(x-3)) = 5 and then simplifying it to x/(x-3) = 1024. They encounter challenges in algebraic manipulation, particularly in isolating x, leading to confusion over basic algebra principles. After several attempts, they derive the solution x = 3072/1023, which simplifies to approximately 3.003. The importance of validating the solution against the original logarithmic conditions is emphasized, confirming that the solution meets the requirement x > 3.
  • #31


Mentallic said:
Not quite, 3*1023=3069

starting over, this is how i work it

log4 x/x-3 = 5

x/x-3 = 4^5

x = 1024 (x-3)

x = 1024x - 3072

x - 1024x = -3072

1023x = -3072

1023x/1023 = -3072/1023

x = -3.003
 
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  • #32


Yes, that is correct- only one step left.

You have 1023x= 3072 and you want x= something. How do you get rid of the "1023" that is multiplying the x?
 
  • #33


HallsofIvy said:
Yes, that is correct- only one step left.

You have 1023x= 3072 and you want x= something. How do you get rid of the "1023" that is multiplying the x?

divide it by 1023
 
  • #34


Now solve for x.
 
  • #35


BloodyFrozen said:
Now solve for x.

x=3.003
 

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