2log(x-1) + logx = logx + log4

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Homework Help Overview

The problem involves the equation 2log(x-1) + logx = logx + log4, which is situated in the context of logarithmic properties and algebraic manipulation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the cancellation of identical logarithmic terms on both sides of the equation, leading to a simplified form. There are attempts to express the equation in terms of logarithmic identities, and some participants express confusion regarding the manipulation of terms and the implications of logarithmic properties.

Discussion Status

The discussion is ongoing with various interpretations being explored. Some participants have provided guidance on how to approach the problem using logarithmic identities, while others are questioning the steps taken and expressing uncertainty about the algebra involved.

Contextual Notes

There are indications of confusion regarding the manipulation of logarithmic expressions and the assumptions about the domain of x, particularly regarding the condition x-1 > 0.

  • #31


Pranav-Arora said:
What are you doing?
6/2=3 and 2-2=0.
Your both the answers are wrong. Correct them.

OMG, such simple mistakes huh, ok

x= 6/2 = 3

x= -(-2) - 2/ 2 = 0/2 x= 0
 
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  • #32


That's too much unnecessary work. From,

(x-1)^2=4

Take the square root of both sides (remember the \pm).
 
  • #33


Mentallic said:
That's too much unnecessary work. From,

(x-1)^2=4

Take the square root of both sides (remember the \pm).

You're right Mentallic but nae99 is doing such silly mistakes here in this thread.

@nae99- take care, since you need to consider this case:- x-1>0
 
  • #34


thanks much
 

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