2log(x-1) + logx = logx + log4

  • Thread starter Thread starter nae99
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The equation 2log(x-1) + logx = logx + log4 simplifies by canceling logx from both sides, leading to log((x-1)^2) = log4. This allows the equation to be further reduced to (x-1)^2 = 4, which can be solved by taking the square root of both sides. The solutions derived from this step are x = 3 and x = -1, but x must be greater than 1 to satisfy the logarithmic condition. Thus, the valid solution is x = 3.
  • #31


Pranav-Arora said:
What are you doing?
6/2=3 and 2-2=0.
Your both the answers are wrong. Correct them.

OMG, such simple mistakes huh, ok

x= 6/2 = 3

x= -(-2) - 2/ 2 = 0/2 x= 0
 
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  • #32


That's too much unnecessary work. From,

(x-1)^2=4

Take the square root of both sides (remember the \pm).
 
  • #33


Mentallic said:
That's too much unnecessary work. From,

(x-1)^2=4

Take the square root of both sides (remember the \pm).

You're right Mentallic but nae99 is doing such silly mistakes here in this thread.

@nae99- take care, since you need to consider this case:- x-1>0
 
  • #34


thanks much
 

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