What is the solution for the equation |x + a| = |x - b|, given that x=2?

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The equation |x + a| = |x - b| has a unique solution at x = 2, leading to the relationship 4 + a = b. The discussion highlights the need to evaluate the values of a and b, with the conclusion that a cannot equal -b when x is fixed at 2. The participants clarify that the assumption of both expressions being positive is incorrect, emphasizing the importance of correctly interpreting absolute values in equations.

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Homework Statement


The equation [tex]\left| {x + a} \right| = \left| {x - b} \right|[/tex] has exactly one solution; at x=2. Find the value(s) of a and b

2. The attempt at a solution
Here is the way in which I have approached the situation:
[tex] \begin{array}{l}<br /> \left| {x + a} \right| = \left| {x - b} \right| \\ <br /> x + a = x + b \\ <br /> \end{array}[/tex]
this solution is not possible as the x's on either side of the equation cancel each other out, and a is not equal to b, so;
[tex] \begin{array}{l}<br /> x + a = - x + b \\ <br /> 2x + a = b \\ <br /> 4 + a = b \\ <br /> a = k \\ <br /> a = k + 4 \\ <br /> \end{array}[/tex]

However I'm not sure on my my final answer, as I have not evaluated the values for a or b, as i have left them in the term of k. However what I have interpreted from the question, I have not been given enough information. Thank you to those who reply, and correct me if anything I have stated is wrong

unique_pavadrin
 
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unique_pavadrin said:

Homework Statement


The equation [tex]\left| {x + a} \right| = \left| {x - b} \right|[/tex] has exactly one solution; at x=2. Find the value(s) of a and b

2. The attempt at a solution
Here is the way in which I have approached the situation:
[tex] \begin{array}{l}<br /> \left| {x + a} \right| = \left| {x - b} \right| \\ <br /> x + a = x + b \\ <br /> \end{array}[/tex]
this solution is not possible as the x's on either side of the equation cancel each other out, and a is not equal to b, so;
[tex] \begin{array}{l}<br /> x + a = - x + b \\ <br /> 2x + a = b \\ <br /> 4 + a = b \\ <br /> a = k \\ <br /> a = k + 4 \\ <br /> \end{array}[/tex]

However I'm not sure on my my final answer, as I have not evaluated the values for a or b, as i have left them in the term of k. However what I have interpreted from the question, I have not been given enough information. Thank you to those who reply, and correct me if anything I have stated is wrong

unique_pavadrin

Not sure how you got this step:
[tex] \begin{array}{l}<br /> \left| {x + a} \right| = \left| {x - b} \right| \\ <br /> x + a = x + b \\ <br /> \end{array}[/tex]
If you are taking both to be positive, it should be [tex]x + a = x - b[/tex]
Then you can kill the x's. so a=-b.
 
thanks for the reply theperthvan

ive used those steps as a simply does not equal -b as the x can be anywhere on the number line. by stating that a=-b, x is a fixed point at zero, which is incorrect as z is given the value of 2

or is that completely wrong?
thanks
 

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