What is the solution to a block sliding on an incline connected to a spring?

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Homework Help Overview

The discussion revolves around a physics problem involving a block sliding on an incline connected to a spring. The block's weight, the incline angle, and the spring's properties are provided, with two main questions regarding the conditions for non-oscillation and the period of oscillation when displaced.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between gravitational force and spring force, with suggestions to use energy conservation and simple harmonic motion concepts. Some participants question the need to consider the incline angle in calculations.

Discussion Status

There are multiple lines of reasoning being explored, particularly regarding the forces acting on the block and how to set up the equations for both parts of the problem. Some participants have offered specific equations and concepts, while others are seeking clarification on their approaches.

Contextual Notes

Participants are working with different parameters for similar problems, which may lead to confusion. There is also a mention of potential errors in applying the equations related to forces and angles.

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shm/spring question, please help!

Homework Statement


A block weighing 16.0 N is able to slide without friction on a 37.0° incline. It is connected to the top of the incline by a massless spring of unstretched length 0.550 m and spring constant 180 N/m.
(a) How far down the incline would you have to place the block so it would not oscillate when you let go?

(b) If the block is pulled slightly down the incline from where you placed in part (a) and released, what is the period of the resulting oscillations?


Homework Equations





The Attempt at a Solution


I have no idea how to even start this problem. Any help is greatly appreciated!
 
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for a) try mgh=1/2*k*x^2
 


don't i need to take into account the angle for part a?
 


yes but that's just trig
 


i'm not sure what you mean
 


For a) you will want to force of the spring to equal the force of gravity on the block acting at that angle.
 


thanks for your help guys!
 


Can someone please explain to me what I'm doing wrong with this problem?

In Fig. 16-35, a block weighing 17.0 N is able to slide without friction on a 32.0° incline. It is connected to the top of the incline by a massless spring of unstretched length 0.475 m and spring constant 110 N/m.

Those are my numbers... I got part B.

I noticed the part where someone said that the force of the spring = Force of gravity. I saw another problem and plugged the numbers in and got the right answer.

The force of spring = kx and
The force of grav = mg cos(theta)

By doing this my answer should be x = [ mg cos (theta) ] / k
which comes out to be about 1.284

This showed up as incorrect. Some guidance about what I'm doing wrong is greatly appreciated.
 
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