What is the solution to Problem 88?

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Homework Help Overview

The discussion revolves around finding the area of the shaded region formed by the intersection of two circles, each with a radius of 3, centered at (-2,0) and (2,0). Participants are exploring the differences in results obtained through calculus and algebraic methods.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss solving for y in the equation of one of the circles and integrating over a specific interval. There are mentions of symmetry in the shape leading to multiplication of results by 4. Questions arise regarding discrepancies between algebraic and calculus-based answers.

Discussion Status

Some participants are attempting to reconcile their results with those found online, while others are questioning the methods used and suggesting that adjustments to angles may be necessary. There is no explicit consensus on the correct approach or answer, but guidance is being offered regarding the need for clarity in problem setup.

Contextual Notes

Participants note that the problem should be approached using calculus rather than geometry, and there are references to specific online resources for comparison. The original poster's reliance on external sources for algebraic methods is also highlighted.

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Homework Statement



http://books.google.com/books?id=gR.... .Find the area of the shaded region&f=false Problem 88

Homework Equations



equation of each circle (x-2)^2+y^2=9
(x+2)^2+y^2=9

The Attempt at a Solution



I solve for y for the circle (x-2)^2+y^2=9 then I took the integral of that from -1 to 0. I noticed that the shape looked symmetrical so I multiplied it by 4. But when I do it algebraically and using geometry I get a different answer then when I use the calculus.
 
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Nobody can say why you are getting different answers until you show how you did it and what you got.
 
Dick said:
Nobody can say why you are getting different answers until you show how you did it and what you got.

Well I really didn't do it algebraically the internet told me how to do it algebraically and it wasn't the same answer I got with my calculus. So the integral of one of the circles is .5(9arcsin(x-2)/3)+(x-2)(9-(x-2)^2)^.5) the limits are from -1 to 0. So I evaluated it and I got 1.584, something around there. And you see the shape is symmetrical on the link I put in. So I mult it by 4 but that did not give the right answer according to the internet. Did I do it the right way.
 
I get something about like that for one fourth of the region. 1.548. I think you are probably right. What's the 'internets' answer?
 
Dick said:
Ok, so what did you put in for the angle? It's likely not the same as in that problem.

I just did the same thing they did except using a my radius of 3 instead of 10. Do you think that my answer is right and maybe what they are doing just doesn't apply in my case. The problem is supposed to be solved using calculus not geometry.
 
Yes, I think your answer is right. And this problem does apply, but you have to change the angle as well, not just radius. If you actually work that example fully through you should get the same answer. In the future, could you state the question more fully before you post, instead of having us guess what your references are?
 
Dick said:
Yes, I think your answer is right. And this problem does apply, but you have to change the angle as well, not just radius. If you actually work that example fully through you should get the same answer. In the future, could you state the question more fully before you post, instead of having us guess what your references are?
I posted a link which should of taken you to the question
 
  • #10
xdrgnh said:
I posted a link which should of taken you to the question

It did. But knowing the question wasn't helping to know what you were doing wrong. Which was your actual question.
 

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