What Is the Solution to sinh(x) = 1?

  • Thread starter Thread starter kd001
  • Start date Start date
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
4 replies · 2K views
kd001
Messages
42
Reaction score
0

Homework Statement



sinh(x) = 1

What is the value of 'x'?


Homework Equations



sinh(x) = (1/2)(e^x - e^-x)


The Attempt at a Solution



e^x - e^-x = 2

Then what do I do?

Thanks
 
Physics news on Phys.org
Multiply the whole eq by [tex]e^{x}[/tex] then solve the resulting quadtatic eqn in [tex]e^{x}[/tex] and afterwards keep the positive solution and take its logarithm to obtain x.
 
emanuel_hr said:
Multiply the whole eq by [tex]e^{x}[/tex] then solve the resulting quadtatic eqn in [tex]e^{x}[/tex]

That is put, say, [tex]u=e^x[/tex] and solve for u. Then find x from [tex]e^x=u[/tex].
 
kd001 said:

Homework Statement



sinh(x) = 1

What is the value of 'x'?


Homework Equations



sinh(x) = (1/2)(e^x - e^-x)


The Attempt at a Solution



e^x - e^-x = 2

Then what do I do?

Thanks
Multiply on both sides by [itex]e^x[/itex] to get [itex](e^x)^2- 1= 2e^x[/itex] and then subtract [itex]2e^x- 1[/itex] from both sides: [itex](e^x)^2- 2e^x= 1[/itex]. Think of that as a quadratic equation in [itex]e^x[/itex] and complete the square: [itex](e^x)^2- 2e^x+ 1= (e^x- 1)^2= 2[/itex].

Take the square root of both sides, [itex]e^x- 1= \pm\sqrt{2}[/itex] and add 1 to both sides, [itex]e^x= 1\pm\sqrt{2}[/itex]. [itex]1- \sqrt{2}< 0[/itex] so you get the single solution [itex]x= ln(1+ \sqrt{2})[/itex].

Too slow! Too slow!