What Is the Solution to sinh(x) = 1?

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Homework Help Overview

The problem involves solving the equation sinh(x) = 1, which is situated in the context of hyperbolic functions and their properties.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss manipulating the equation by multiplying through by e^x and reformulating it as a quadratic equation in e^x. There are questions about the next steps after reaching the quadratic form.

Discussion Status

Some participants have provided guidance on how to approach solving the quadratic equation, while others have confirmed that the suggested methods were effective. Multiple interpretations of the steps involved are being explored.

Contextual Notes

There are repeated statements of the problem and attempts to clarify the steps involved in solving the equation, indicating a focus on understanding the manipulation of hyperbolic functions.

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Homework Statement



sinh(x) = 1

What is the value of 'x'?


Homework Equations



sinh(x) = (1/2)(e^x - e^-x)


The Attempt at a Solution



e^x - e^-x = 2

Then what do I do?

Thanks
 
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Multiply the whole eq by e^{x} then solve the resulting quadtatic eqn in e^{x} and afterwards keep the positive solution and take its logarithm to obtain x.
 
emanuel_hr said:
Multiply the whole eq by e^{x} then solve the resulting quadtatic eqn in e^{x}

That is put, say, u=e^x and solve for u. Then find x from e^x=u.
 
Thanks. That worked.
 
kd001 said:

Homework Statement



sinh(x) = 1

What is the value of 'x'?


Homework Equations



sinh(x) = (1/2)(e^x - e^-x)


The Attempt at a Solution



e^x - e^-x = 2

Then what do I do?

Thanks
Multiply on both sides by e^x to get (e^x)^2- 1= 2e^x and then subtract 2e^x- 1 from both sides: (e^x)^2- 2e^x= 1. Think of that as a quadratic equation in e^x and complete the square: (e^x)^2- 2e^x+ 1= (e^x- 1)^2= 2.

Take the square root of both sides, e^x- 1= \pm\sqrt{2} and add 1 to both sides, e^x= 1\pm\sqrt{2}. 1- \sqrt{2}< 0 so you get the single solution x= ln(1+ \sqrt{2}).

Too slow! Too slow!
 

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