What is the solution to this relative motion problem?

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Homework Help Overview

The discussion revolves around a relative motion problem involving a man trying to cross a river and end up directly opposite his starting point on the opposite shore. The problem is situated within the context of kinematics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the man's intended direction and the river's current on his final position. There are differing interpretations of the question regarding the necessary angle of travel and the resulting ground velocity.

Discussion Status

The discussion is ongoing, with participants questioning the assumptions about the man's path and the effects of the river's current. Some guidance has been offered regarding the need to consider the angle of travel to achieve the desired endpoint, but no consensus has been reached.

Contextual Notes

There is mention of differing interpretations of the question, particularly regarding the terms "actual motion" and "ground velocity." The original poster's teacher has provided feedback that may influence the understanding of the problem.

temaire
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Homework Statement


http://img221.imageshack.us/img221/5571/kinematicslz1.jpg
I asked my teacher to clarify this question a bit more, and she said that the man wanted to end up exactly opposite to where he was on the west shore, or in other words, parallel to where he was from the east shore.

Homework Equations


soh cah toa
[tex]a^{2} + b^2 = c^2[/tex]


The Attempt at a Solution


I think that the answer is B), because in order for him to end up exactly opposite of where he is, he must go west.
However, my teacher thinks that the answer is D). Who's right?
 
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Can anyone help?
 
If he goes straight west, he won't land directly opposite of his starting position, since the river will have pushed him north. Therefore he must travel at some angle south of west.
 
Sorry, I meant to say that the man wanted to go straight west, so he had to go 10kkm/h at an angle. But the question is asking for the actual velocity, or in other words, the ground velocity, which is, as I think, 8.0 km/h west.
 
Yes, I suppose it depends on your interpretation of the question then.
 
Well it says actual motion.
 

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