What Is the Specific Heat Capacity of Cream?

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SUMMARY

The specific heat capacity of cream was calculated based on a scenario where 300 kg of water at 90ºC loses heat while heating 250 kg of cream from 5ºC to 60ºC. The heat lost by the water was determined to be -37,800 kJ. Consequently, the specific heat capacity of the cream was calculated to be 2,749 J/kgºC using the formula Q = mcΔT, confirming the approach taken in the calculations was correct.

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  • Understanding of heat transfer principles
  • Familiarity with the specific heat capacity formula Q = mcΔT
  • Basic knowledge of thermodynamics
  • Ability to perform unit conversions and calculations
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  • Learn about the specific heat capacities of various substances
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Priscilla
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Homework Statement



The cream is kept at 5 ºC in the lorries. It is pumped into silos, where it is pre-heated before being pasteurized. The silos are jacketed, and hot water is pumped through the jacket. Assuming no losses, if 300 kg of water at 90ºC enters the jacket and exits at 60 ºC, resulting in 250 kg of cream present in the silo being heated to 60oC, calculate:
a. The amount of heat lost by the water in the jacket of the silo.
b. The heat capacity of the cream
(Heat capacity of water is 4200 J/kg K)

Homework Equations



Q= mc(delta)T


The Attempt at a Solution



a) Q = (300kg)(4200J/kg ºC) (60ºC - 90ºC) = -3.78e4kJ
b) 3.78e4kJ = (250kg)(C)(60ºC - 5ºC)
C = 2749J/kgºC


I don't know if I did it right or not. Please check for me.
 
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I have not checked numbers, but approach is correct.
 

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