- #1
aruhland
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- Homework Statement
- A 0.009089 mol sample of an organic compound was burned in oxygen in a bomb calorimeter. The temperature of the calorimeter increased from 24.3 C to 31.1 C. If the heat capacity of the calorimeter is 4.38 kj/C, what is the constant volume heat of combustion of this compound, in kj/mol?
- Relevant Equations
- Qcal=heat capacity calorimeter * change in temperature
Q=nCdeltaT
Qcal=-Qrxn
Q=heat capacity calorimeter*(-)change in T*moles
=0.009089mol*-6.8C*4.38kj/C
=-0.2707kj/mol
This answer is wrong but it was the only one I could come up with right now. I just noticed units in the answer would be wrong too. Any suggestions?
=0.009089mol*-6.8C*4.38kj/C
=-0.2707kj/mol
This answer is wrong but it was the only one I could come up with right now. I just noticed units in the answer would be wrong too. Any suggestions?