What is the speed of a killer whale as it jumps 6.6 m above the water?

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Killer whales at Sea World can achieve a speed of 11.37 m/s when jumping 6.6 meters above the water. This calculation is derived using the kinematic equation v² = u² + 2as, where the final velocity (v) at the peak of the jump is 0 m/s, the acceleration (a) is -9.8 m/s² (due to gravity), and the distance (s) is 6.6 m. The initial velocity (u) required for this jump is determined to be 11.37 m/s.

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Killer whales at Sea World routinely jump 6.6 m above the water. What is their speed as they leave the water to achieve this?
____m/s

I don't know what to do.
Thanks in advance to anyone who posts
 
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use the equation
v^2 = u^2 + 2 a s
look up your textbook if you have no idea what is this formulas about...
 
From launch to when it reaches the top of its motion, (V2)=0 m/s.
So: (V2)^2=(V1)^2 + 2 (acc.) (dist.)
0 = (V1)^2 + 2*(-9.8)*(6.6)
(V1) = 11.37 m/s
 

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