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## Homework Statement

A bungee jumper of mass 60kg jumps from a bridge 24 m above the surface of the water. The rope is 12 m long and is assumed to obey Hooke's law. What should the spring constant of the rope be if the woman is to just reach the water?

## Homework Equations

Ep=mgh

E=1/2 kx^2

## The Attempt at a Solution

Energy conservation? I'm definitely doing something wrong here and not understanding something but I don't know what.

mgh = ½kx^2

(60)(10)(12) = ½k(12)^2

[I put the length of the unstretched part of the rope as my

*h*value and

*x*as the extension, which is 24-12=12]

k= 100 Nm^-1

[This is the answer I got]

But the answer is k=200 Nm^-2