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[Mechanics] Tension in bungee jumping

  1. Apr 24, 2016 #1
    1. The problem statement, all variables and given/known data
    A bungee jumper of mass 60kg jumps from a bridge 24 m above the surface of the water. The rope is 12 m long and is assumed to obey Hooke's law. What should the spring constant of the rope be if the woman is to just reach the water?

    2. Relevant equations
    E=1/2 kx^2

    3. The attempt at a solution
    Energy conservation? I'm definitely doing something wrong here and not understanding something but I don't know what.

    mgh = ½kx^2
    (60)(10)(12) = ½k(12)^2
    [I put the length of the unstretched part of the rope as my h value and x as the extension, which is 24-12=12]

    k= 100 Nm^-1
    [This is the answer I got]

    But the answer is k=200 Nm^-2
  2. jcsd
  3. Apr 24, 2016 #2

    Doc Al

    User Avatar

    Staff: Mentor

    To calculate the initial gravitational PE, use the height above the water.
  4. Apr 24, 2016 #3
    okay thanks!
  5. Apr 24, 2016 #4
    This is the key statement : The woman jumps from a bridge 24 m above the surface of water.
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