What is the Speed of the Speeder Relative to the Ground?

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SUMMARY

The discussion focuses on calculating the speed of a speeder relative to the ground, given that a police car is moving at 27 m/s and emits a radar wave with a frequency of 7.2 x 109 Hz. The reflected frequency measured is 310 Hz less than the emitted frequency. Using the formula for relative velocity, the calculated relative velocity is 12.92 m/s. Therefore, the speeder's speed relative to the ground is determined to be either 14 m/s or 40 m/s, with the latter being more indicative of a speeder's speed.

PREREQUISITES
  • Understanding of the Doppler effect in electromagnetic waves
  • Familiarity with basic physics equations related to relative velocity
  • Knowledge of frequency, wavelength, and speed of light
  • Ability to convert units from meters per second to miles per hour
NEXT STEPS
  • Study the Doppler effect and its applications in radar technology
  • Learn how to derive and manipulate equations for relative velocity
  • Explore the conversion methods between metric and imperial units
  • Investigate real-world applications of radar speed detection in law enforcement
USEFUL FOR

Students studying physics, law enforcement professionals using radar technology, and anyone interested in the practical applications of the Doppler effect in speed measurement.

arod2812
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Homework Statement


A speeder is pulling directly AWAY and INCREASING his distance from a police car that is moving at 27 m/s with respect to the ground. The radar gun in the police car emits an electromagnetic wave with a frequency of 7.2 x 109 Hz. The wave reflects from the speeder's car and returns to the police car, where its frequency is measured to be 310 Hz less than the emitted frequency. Find the speeder's speed with respect to the ground.


Homework Equations


WHAT do I do with the answer that I get for relative velocity?
DO I subtract the 27 m/s from the 12.92 that I got as an answer??

The Attempt at a Solution



fo=fs (1+Vrel/c)
Then I rearranged the equation to solve for the relative velocity.

I got: [(Change in frequency)/fs] * speed of light = relative velocity
which is 310 Hz/7.2E9 *3E8 = 12.92
 
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If the cop is moving at 27 m/s, and according to the cop the speeder is moving at 13 m/s, then what is the speeder's speed?? That, my friend, is an easy question. You've done the hard part already. Ponder this: 27-13 is 14 m/s, and 27+13 is 40 m/s. Convert these to mph and you tell me which one is more likely to represent a speeder.
 
gotcha. thanks!
 

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