What is the speed of the water in the Bernoulli River?

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The discussion revolves around calculating the speed of water in the Bernoulli River, formed by the confluence of River Pascal and River Archimedes. The combined volume flow rates are 4.7×10^5 L/s and 1.1×10^6 L/s, with the Bernoulli River having a width of 130 meters and a depth of 30 meters. Initial attempts at calculating the speed yielded incorrect results, with guesses of 0.120 m/s and 1.20 m/s. After clarifying the need to consider both rivers' flow rates, the correct speed was determined to be 0.40 m/s. The discussion emphasizes the importance of using the total flow rate for accurate calculations.
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Homework Statement


River Pascal with a volume flow rate of 4.7×105 joins with River Archimedes, which carries 1.1×106 , to form the Bernoulli River. The Bernoulli River is 130 wide and 30 deep.

What is the speed of the water in the Bernoulli River?

Homework Equations


Express your answer using two significant figures.


The Attempt at a Solution


I attempted to guesses so far.
0.120 m/s was wrong
1.20 m/s was wrong



Thanks for all the help.
Jared
 
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Welcome to PF!

Hi Jared! Welcome to PF! :smile:

(try using the X2 tag just above the Reply box :wink:)
Beastegargoyl said:
River Pascal with a volume flow rate of 4.7×105 joins with River Archimedes, which carries 1.1×106 , to form the Bernoulli River. The Bernoulli River is 130 wide and 30 deep.

What is the speed of the water in the Bernoulli River?

I attempted to guesses so far.
0.120 m/s was wrong
1.20 m/s was wrong

Show us your full calculations, and then we can see what went wrong, and we'll know to help! :smile:
 
For vfr=4.7*105L/s

I used the equation 4.7*105/3900 equals 1.2m/s

Thanks for the help.
Jared
 
Hi Jared! :smile:

(just got up :zzz: …)
Beastegargoyl said:
River Pascal with a volume flow rate of 4.7×105 joins with River Archimedes, which carries 1.1×106 , to form the Bernoulli River. The Bernoulli River is 130 wide and 30 deep.

What is the speed of the water in the Bernoulli River?

Beastegargoyl said:
For vfr=4.7*105L/s

I used the equation 4.7*105/3900 equals 1.2m/s

oh i see … you only used the volume flow rate of River Pascal.

The Bernoulli River contains the water of both River Pascal and River Archimedes. :wink:
 
@tiny-tim- Did you come up with an answer of .40m/s where that incportates both rivers?

Thanks for your help,

Jared
 
Beastegargoyl said:
@tiny-tim- Did you come up with an answer of .40m/s where that incportates both rivers?

I go 4.0 times something

what are the units of the problem? :confused:
 
4.7*105L/s and 1.1*106L/s. 130m wide and 30m deep.

The answer needs to be expressed in m/s.
 
Beastegargoyl said:
4.7*105L/s and 1.1*106L/s. 130m wide and 30m deep.

The answer needs to be expressed in m/s.

oh, litres! :rolleyes:

ok, then i make it .40m/s :smile:
 

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