What is the spring constant of the spring

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SUMMARY

The spring constant of the spring is calculated to be 1000 N/m based on the elongation of 0.05m under a 50N force. When a 10kg mass is applied, the spring elongates by 0.098m. The energy stored in the spring system with the 10kg mass is determined to be 4.802 Joules. The unit of energy is confirmed to be Joules, equivalent to kg⋅m²/s².

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  • Basic physics concepts including force, mass, and gravity
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A spring elongates 0.05m when a 50N is applied to it

a) What is the spring constant of the spring

b) How long would the spring elongate if a 10kg mass is hung from the spring

c) If the energy stored in the spring of parts a) and b) is given by

E=0.5kx², how much energy is stored in the spring mass system of part b) g=10m/s²

I got a) which is k = 1000 N/m

b) i believe is 0.098m, k=m*g/k

c) is 4.802

I just want to verify if these are correct
 
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I agree with those answers.
 


by the way what are the units for c?
 


The unit of energy is the Joule.
According to E = ½mv², a Joule (J) is equivalent to a kg⋅m²/s².
 

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