What is the Static Equilibrium of a Pulley System?

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SUMMARY

The discussion focuses on a static equilibrium problem involving a pulley system with a 0.5 kg mass on one side and a 2.0 kg mass on the other. The pulley is frictionless, and the string is massless. The tension in the string can be calculated using the equation t - (2 * 9.8) = F, where t represents tension and 9.8 m/s² is the acceleration due to gravity. The normal force acting on the 2.0 kg box is equal to its weight, which is 2.0 kg * 9.8 m/s².

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Homework Statement



A system with a pulley, string, and mass has a string on a pulley holding 0.5 kg on one end and 2.0 kg on the other. It is in static equilibrium; the pulley is frictionless; the string is massless.
What is the tension in the string holding the pulley?
What is the value of the normal force on the 2.0 kg box?

Homework Equations



f=ma


The Attempt at a Solution



t-(2*9.8)=F? (part a)
 
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hi runningirl! :smile:
runningirl said:
A system with a pulley, string, and mass has a string on a pulley holding 0.5 kg on one end and 2.0 kg on the other. It is in static equilibrium; the pulley is frictionless; the string is massless.
What is the tension in the string holding the pulley?
What is the value of the normal force on the 2.0 kg box?

t-(2*9.8)=F? (part a)

is the 2.0 kg mass resting on the ground?

if so, always start with the mass with the least number of forces acting on it (because that's easiest! :biggrin:), and then work your way round to the others

in this case, that's the 0.5 kg mass …

so what is the ∑F = 0 equation for that? :smile:
 

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