The strength of the magnetic field in a solenoid can be calculated using the formula B = μ₀ * n * I / l, where μ₀ is the permeability of free space (4π x 10^-7 T·m/A), n is the number of turns per unit length, I is the current in amperes, and l is the length of the solenoid. In this case, a solenoid of 0.20 m length with 1000 turns and a current of 5.0 A yields a calculated magnetic field strength of 3.14 x 10^-2 T. However, the answer key states the correct value is 6.3 x 10^-3 T, indicating a discrepancy that may arise from misinterpretation of the parameters or calculation errors.
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physgrl said:Homework Statement
A 0.20 m long solenoid contains 1000 turns and carries a current of 5.0 A. What is the strength of the magnetic field at the center of the solenoid if its radius is 10-2m?
a. 35.1*10-1T
b. 8.2*10-1T
c. .95*10-2T
*d. 6.3*10-3T
Homework Equations
B=μo*nI/l
The Attempt at a Solution
B=(4∏*10^-7)*1000*5A/.2m
B=3.14x10^-2T
the answer key says its 6.3x10^-3T...what am I doing wrong?