The discussion focuses on calculating the tension force in two blocks on an incline, emphasizing that one cannot assume a fixed tension value, such as 1500N, for block B. Instead, the tension should be represented as "T" in the equations. The blocks, connected by a rope, share the same acceleration, which is derived from applying Newton's 2nd law to each block separately, resulting in two equations with two unknowns. The forces acting on block A include tension and friction, both directed up the incline.
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You cannot assume any value for the tension. Just call it "T" and include it in your analysis.sash187 said:
The blocks are connected by a rope, so they have the same acceleration.
That would work.sash187 said:
Both the tension and the friction force on block A act up along the incline (North East, if you like). I don't know what you mean by the 'MA force'. The acceleration is down the incline.
That's not a force, that's mass*acceleration. If you were to list the forces acting on either block, you would not include 'mass*acceleration'. That term appears when you apply Newton's 2nd law.sash187 said: