- #1

A_lilah

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## Homework Statement

3.7 kg block A and 6.0 kg block are connected by a string of negligable mass. Force FA = (13 N) acts on block A; force FB = (24 N) acts on block B. What is the tension in the string? (both force FA and FB are to the right)

## Homework Equations

fnet = ma

## The Attempt at a Solution

Block A FBD:

Weight force down of m*g = 36.297N

Normal force up (opposite of weight)

frictional force to the left = f1

FA to the right = 13N

Tension, T, to the right

Block B FBD:

Weight force down = 58.8N

Normal force up (opposite of weight)

frictional force to the right = f2

FB to the right = 24 N

Tension force, T, to the left

equations:

Fnet Ax = 3.7kg * a = 13N + T - f1

Fnet Bx = 6kg * a = 24N -T + f2

Fnet of A and B together = 9.7 kg * a = 37N + f2 -f1

Problem: four unknowns and only three equations...