What is the threshold energy for gamma+e→3e and gamma→e⁺e⁻ reactions?

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SUMMARY

The threshold energy for the gamma + e → 3e reaction is derived using the equation E² - P² = W², where W represents the total center of mass energy. The specific calculation involves substituting k (the energy of the gamma quantum) and m (the mass of the electron) into the equation, resulting in (k + m)² - k² = (3m)². This establishes the energy required to produce three electrons in the presence of a stationary electron.

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Starwanderer1
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Can someone help me out with this problem(not homework ofcourse)..

Find the threshold energy of gamma quantum required to form
- an electron-positron pair in the field of a stationary electron;
- a pair of pions of opposite signs in the field of a stationary proton..

Thank you for reading
 
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Use [tex]E^2-P^2=W^2[/tex], where W= total cm energy.
For gamma+e-->3e, this becomes [tex](k+m)^2-k^2=(3m)^2.[/tex]
 

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