What is the time constant of the cooled steel billet?

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SUMMARY

The time constant τ for the cooling process of an alloy-steel billet, initially at 1032°F and cooled in a 32°F air stream, can be calculated using the equation T = T∞ + (Ti-T∞)e-t/τ. Here, T∞ is 32°F and Ti is 1032°F. The concept of exponential decay indicates that after one time constant, the temperature will have decreased by 63.2% of the difference between the initial and ambient temperatures, leaving 36.8% of the difference remaining. Therefore, to find τ, one must determine the time it takes for the temperature to reach approximately 63.2% of the way to the ambient temperature.

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16. As part of a heat-treating process, an alloy-steel billet, initially at 1032°F, is cooled in a 32°F air stream. The temperature history of the billet is shown in the figure at right.
What is the time constant τ for the cooling process?

I have attached an image of the question.

I have the equation:

T = T + (Ti-T)e-t/τ

I know that:

T = 32°F

Ti = 1023°F

But I'm a little uncertain about the time. If I take the max temperature value, 1032°F, and multiply this by 0.368, would this give me the time and temperature at one time constant?
 

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Exponential decay is based on the difference value, the difference between where it is now and where it is headed finally. In one time constant it closes the distance by 63.2% leaving 36.8% of that difference to go.
 

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