What is the Time Required for a Transverse Wave to Travel in a Whirled Rope?

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pjkily
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Homework Statement



a uniform rope with length L and mass M is held at one end and whirled in a horizontal circle with angular velocity [tex]\omega[/tex]. you can ignore the force of gravity on the rope. find the time required for a transverse wave to travel from one end of the rope to the other.


Homework Equations



v=(T/[tex]\mu[/tex])^(1/2) where [tex]\mu[/tex]=density
[tex]\Sigma[/tex]F=ma

The Attempt at a Solution


This is the solution that the professor gave, but i don't understand why:

[tex]\Sigma[/tex]F=F[tex]_{T}[/tex]=[tex]\Delta[/tex]a[tex]_{c}[/tex]
dF[tex]_{T}[/tex]=(dm)r[tex]\omega[/tex][tex]^{2}[/tex]
dF[tex]_{T}[/tex]=[tex]\mu[/tex]r[tex]\omega[/tex][tex]^{2}[/tex]dr
integrate with respect to r, from r to t.

I
 
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Welcome to PF!

Hi pjkily! Welcome to PF! :smile:

(have a square-root: √ and a mu: µ and an omega: ω and a sigma: ∑ and a delta: ∆ :wink:)
pjkily said:
a uniform rope with length L and mass M is held at one end and whirled in a horizontal circle with angular velocity [tex]\omega[/tex]. you can ignore the force of gravity on the rope. find the time required for a transverse wave to travel from one end of the rope to the other.

The tension, T (no need to call it FT :wink:) increases towards the end of the string.

And the speed depends on the tension.

So you need to integrate along the string. :smile:
 
OH! that's the part I didn't understand.
THANK YOU SOOOO MUCH, Tim!