What is the Time to Fill a Tank with Pipe B Only?

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Homework Help Overview

The problem involves determining the time it takes to fill a tank using only Pipe B, given that Pipe A flows five times faster than Pipe B and both pipes together can fill the tank in 4 hours.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the flow rates of the pipes and question the interpretation of the problem's conditions. Some express confusion about the implications of the rates when only one pipe is used.

Discussion Status

There is ongoing exploration of the problem's setup, with participants attempting to clarify the flow rates and the total volume of the tank. Some have suggested specific values to simplify calculations, while others are seeking to confirm their understanding of the relationships between the flow rates.

Contextual Notes

Participants note the lack of specific information about the tank's volume and the assumptions made to facilitate calculations. There is acknowledgment of the problem's vagueness and the challenges it presents in interpretation.

puma072806
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I understand this is a basic problem. For some reason I just can't wrap my head around it. Any help is appreciated.

Homework Statement


Water flows through Pipe A five times faster than through Pipe B. When water flows through the both pipes a tank would be filled in 4 hours. How long will it take to fill a tank if only Pipe B opened?



Homework Equations





The Attempt at a Solution


Pipe A: (5x)
Pipe B: (x)
Time: four hours.
 
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So if both pipes flow, it takes 4 hours but if only pipe B flows then it ALSO takes 4 hours ? Does that seem likely to you?
 
I presume the problem means to say that the volume of water passing through pipe A is 5 times greater than the volume passing through pipe B. If water flows through both pipes, how many times the volume of pipe B is flowing?
 
Skeptic2 is right as far as interpreting the problem goes. Can anyone help me out?!
Thanks.
 
You've written that water flows through A at rate 5x and through B at rate x. If both flowing, what's the total rate? If that takes 4 hours to fill, how big is the tank?
 
Your "attempt at a solution" says that pipe B delivers an amount x of water in a specified time to the tank. And pipe A delivers an amount 5x to the tank in the same time.

So how much do A and B deliver to the tank together (again, in the time we're using in these measurements)?
 
puma072806 said:
Skeptic2 is right as far as interpreting the problem goes. Can anyone help me out?!
Thanks.
Answering Skeptic2's question at the end of his post should help you out.
 
That's all the info that the problem gives.
Like I said I'm sure this is really easy for most people but I just can't wrap my head around it.
 
So if A can deliver 5 liters per second and B can deliver 1 liter per second, how many liters per second can A plus B deliver?
 
  • #10
6 liters per second
So would it take six hours to fill the tank if only B were open? Or 5?
 
  • #11
puma072806 said:
6 liters per second
So would it take six hours to fill the tank if only B were open? Or 5?

You are not even close.

I've found that the best way to solve these "vague" problems is to make them specific and to do so in a way that simplifies the calculations.

Since you have a speed X and a speed 5X, ASSUME that your tank contains 6 liters (that the one plus the 5). From this you can deduce a value for X. Then you can go back and see what effect 1X would have, given that you know what effect 6X has.
 
  • #12
So if at 6 liters per second it takes 4 hours to fill the tank, how big is the tank?

Ans.: 4 hr x 3600 sec/hr x 6 liters / sec. = 86400 liters.

How many hours would it take to fill the tank at 1 liter/sec?
 
Last edited:
  • #13
Thanks everybody for all your help. I was able to figure it out with your help.

I got 24 hours as the final answer and the professor said it was correct.
Thanks again!
 

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