What is the Total Momentum After Two People Push Each Other on Ice Skates?

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SUMMARY

The total momentum after two people, with masses of 52 kg and 77 kg, push off each other on ice skates is zero. This conclusion is derived from the principle of conservation of momentum, which states that the total momentum before the push is equal to the total momentum after the push. Since both individuals start from rest, their initial velocities are zero, leading to a final momentum of zero regardless of their respective velocities after the push. The relevant equation used is P = Pa + Pb, confirming that the system's momentum remains conserved.

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Homework Statement



two persons on ice skates stand face to face and then push each other away. their masses are 52 kg and 77 kg. what is the total momentum after they have pushed off

Homework Equations


the equation that would be most useful here would be P=Pa+Pb the equation for total momentum


The Attempt at a Solution



Im stump on this problem. Two mass are given, but no velocity is displayed. can someone explain to me.
 
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Is there any other equation involving momentum that you think could be relevant?
 
Jilang said:
Is there any other equation involving momentum that you think could be relevant?

well I can think of the conservation of momentum equation: m1v1(initial)+m2v2(initial)=m1v1(final)+m2v2(final)

you think I can use this equation?
 
Yes that's a good equation!
 
Momentum is initially zero,, what clues does that give you
 
Dan350 said:
Momentum is initially zero,, what clues does that give you

that the final momentum will be given with their respected velocities.

0+0=52kgv1(final)+77kgv2(final). But I still don't see a way to solve this. Unless I factor the v(final)?
 
after reviewing it I realize that the total momentum would zero. Because of the fact that only the masses are given and there's no other way to compute this.
 

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