MHB What is the transfer function for this system?

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In long-distance telephone communication, echoes can occur due to signal reflections, complicating the transmission process. The impulse response for this system is modeled as \( h(t) = \alpha\ \delta(t - T) + \alpha^{3}\ \delta(t - 3T) \), leading to the transfer function \( H(s) = \alpha\ e^{-sT} + \alpha^{3}\ e^{-3sT} \). It is noted that \( H(s) \) does not have any zeros or poles, as it consists solely of exponential terms representing pure delays. The only conditions under which \( H(s) \) could be zero involve specific values of \( \alpha \). This highlights the nature of the system's response in terms of signal delay rather than traditional pole-zero behavior.
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In a long-distance telephone communication, an echo is sometimes encountered due to the transmitted signal being reflected at the receiver, sent back down the line, reflected again at the transmitter, and returned to the receiver. The impulse response for a system that modles this effect is shown in figure, where we have assumed tat only one echo is received. The parameter \(T\) corresponds to the one-way travel time along the communication channel, and the parameter \(\alpha\) represents the attenuation in amplitude between transmitter and receiver.
View attachment 2099
Determine the system function \(H(s)\) and associated region of convergence for the system.

How can I determine a transfer function from this?
 

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dwsmith said:
In a long-distance telephone communication, an echo is sometimes encountered due to the transmitted signal being reflected at the receiver, sent back down the line, reflected again at the transmitter, and returned to the receiver. The impulse response for a system that modles this effect is shown in figure, where we have assumed tat only one echo is received. The parameter \(T\) corresponds to the one-way travel time along the communication channel, and the parameter \(\alpha\) represents the attenuation in amplitude between transmitter and receiver.
View attachment 2099
Determine the system function \(H(s)\) and associated region of convergence for the system.

How can I determine a transfer function from this?

Is...

$\displaystyle h(t) = \alpha\ \delta(t - T) + \alpha^{3}\ \delta (t - 3\ T)\ (1)$

... so that...

$\displaystyle H(s) = \alpha\ e^{- s\ T} + \alpha^{3}\ e^{- 3\ s\ T}\ (2)$

Kind regards

$\chi$ $\sigma$
 
chisigma said:
Is...

$\displaystyle h(t) = \alpha\ \delta(t - T) + \alpha^{3}\ \delta (t - 3\ T)\ (1)$

... so that...

$\displaystyle H(s) = \alpha\ e^{- s\ T} + \alpha^{3}\ e^{- 3\ s\ T}\ (2)$

Kind regards

$\chi$ $\sigma$

We know that exponential are never zero. How can we represent \(H\) in terms of zeros and poles? The only time I see that \(H\) can be zero is if \(\alpha = 0, \pm i\) but is that right?
 
dwsmith said:
We know that exponential are never zero. How can we represent \(H\) in terms of zeros and poles? The only time I see that \(H\) can be zero is if \(\alpha = 0, \pm i\) but is that right?

The answer is very simple: in this case H(s) doesn't have neither zeros neither poles but only 'pure delays'...

Kind regards

$\chi$ $\sigma$
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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