What is the transfer function for this system?

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SUMMARY

The transfer function for a long-distance telephone communication system experiencing echo is defined as \(H(s) = \alpha e^{-sT} + \alpha^3 e^{-3sT}\). The impulse response is given by \(h(t) = \alpha \delta(t - T) + \alpha^3 \delta(t - 3T)\). The parameters \(T\) and \(\alpha\) represent the one-way travel time and amplitude attenuation, respectively. Notably, the system does not exhibit zeros or poles, as it consists solely of pure delays.

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In a long-distance telephone communication, an echo is sometimes encountered due to the transmitted signal being reflected at the receiver, sent back down the line, reflected again at the transmitter, and returned to the receiver. The impulse response for a system that modles this effect is shown in figure, where we have assumed tat only one echo is received. The parameter \(T\) corresponds to the one-way travel time along the communication channel, and the parameter \(\alpha\) represents the attenuation in amplitude between transmitter and receiver.
View attachment 2099
Determine the system function \(H(s)\) and associated region of convergence for the system.

How can I determine a transfer function from this?
 

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dwsmith said:
In a long-distance telephone communication, an echo is sometimes encountered due to the transmitted signal being reflected at the receiver, sent back down the line, reflected again at the transmitter, and returned to the receiver. The impulse response for a system that modles this effect is shown in figure, where we have assumed tat only one echo is received. The parameter \(T\) corresponds to the one-way travel time along the communication channel, and the parameter \(\alpha\) represents the attenuation in amplitude between transmitter and receiver.
View attachment 2099
Determine the system function \(H(s)\) and associated region of convergence for the system.

How can I determine a transfer function from this?

Is...

$\displaystyle h(t) = \alpha\ \delta(t - T) + \alpha^{3}\ \delta (t - 3\ T)\ (1)$

... so that...

$\displaystyle H(s) = \alpha\ e^{- s\ T} + \alpha^{3}\ e^{- 3\ s\ T}\ (2)$

Kind regards

$\chi$ $\sigma$
 
chisigma said:
Is...

$\displaystyle h(t) = \alpha\ \delta(t - T) + \alpha^{3}\ \delta (t - 3\ T)\ (1)$

... so that...

$\displaystyle H(s) = \alpha\ e^{- s\ T} + \alpha^{3}\ e^{- 3\ s\ T}\ (2)$

Kind regards

$\chi$ $\sigma$

We know that exponential are never zero. How can we represent \(H\) in terms of zeros and poles? The only time I see that \(H\) can be zero is if \(\alpha = 0, \pm i\) but is that right?
 
dwsmith said:
We know that exponential are never zero. How can we represent \(H\) in terms of zeros and poles? The only time I see that \(H\) can be zero is if \(\alpha = 0, \pm i\) but is that right?

The answer is very simple: in this case H(s) doesn't have neither zeros neither poles but only 'pure delays'...

Kind regards

$\chi$ $\sigma$
 

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