cocopops12
- 30
- 0
Could anyone please tell me how are those two expressions equivalent?! what are the identities used?
What is the trigonometric identity used to simplify this expression?
- Context: Undergrad
- Thread starter cocopops12
- Start date
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
Could anyone please tell me how are those two expressions equivalent?! what are the identities used?
Discussion
Staff Emeritus
Science Advisor
Gold Member
- 5,706
- 1,592
It's not a trig identity
[tex]\frac{1}{1-\sin z} = \frac{1+\sin z}{1+\sin z} \frac{1}{1-\sin z} = \frac{1+\sin z}{1-\sin^2 z}[/tex]
[tex]\frac{1}{1-\sin z} = \frac{1+\sin z}{1+\sin z} \frac{1}{1-\sin z} = \frac{1+\sin z}{1-\sin^2 z}[/tex]