cocopops12
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Could anyone please tell me how are those two expressions equivalent?! what are the identities used?
What is the trigonometric identity used to simplify this expression?
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Could anyone please tell me how are those two expressions equivalent?! what are the identities used?
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It's not a trig identity
[tex]\frac{1}{1-\sin z} = \frac{1+\sin z}{1+\sin z} \frac{1}{1-\sin z} = \frac{1+\sin z}{1-\sin^2 z}[/tex]
[tex]\frac{1}{1-\sin z} = \frac{1+\sin z}{1+\sin z} \frac{1}{1-\sin z} = \frac{1+\sin z}{1-\sin^2 z}[/tex]