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What is the trigonometric identity used to simplify this expression?

  1. Mar 23, 2012 #1
    2ut1ag9.png

    Could anyone please tell me how are those two expressions equivalent?! what are the identities used?
     
  2. jcsd
  3. Mar 23, 2012 #2

    Office_Shredder

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    It's not a trig identity

    [tex] \frac{1}{1-\sin z} = \frac{1+\sin z}{1+\sin z} \frac{1}{1-\sin z} = \frac{1+\sin z}{1-\sin^2 z} [/tex]
     
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