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What is the trigonometric identity used to simplify this expression?

  1. Mar 23, 2012 #1

    Could anyone please tell me how are those two expressions equivalent?! what are the identities used?
  2. jcsd
  3. Mar 23, 2012 #2


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    It's not a trig identity

    [tex] \frac{1}{1-\sin z} = \frac{1+\sin z}{1+\sin z} \frac{1}{1-\sin z} = \frac{1+\sin z}{1-\sin^2 z} [/tex]
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