What is the Uncertainty in Wavelength for an Excited Atomic State?

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Homework Help Overview

The discussion revolves around determining the uncertainty in wavelength for a photon emitted during the decay of an excited atomic state with a specified lifetime. The problem involves concepts from quantum mechanics, particularly relating to energy-time uncertainty and the relationship between energy and wavelength.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the energy-time uncertainty principle and its implications for calculating uncertainties in wavelength. There is an attempt to derive the uncertainty in energy and subsequently in wavelength, with some questioning the physicality of the results obtained.

Discussion Status

Some participants affirm the method being used, while others express concerns about the resulting values being unphysical. There is ongoing exploration of the relationships between energy, frequency, and wavelength, with suggestions to consider different approaches to clarify the calculations.

Contextual Notes

Participants are working under the constraints of the problem statement, which includes specific values for lifetime and wavelength. There is a noted confusion regarding the application of certain equations and the assumptions made in the calculations.

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Homework Statement



An excited atomic state has a lifetime of 1 ms.

What is the uncertainty in its energy?

The photon emitted during its decay is 550 nm in wavelength. What is the uncertainty and fractional uncertainty in its wavelength?

Homework Equations



ΔEΔt≥hbar/2

The Attempt at a Solution



a. Straightforward plugging into the equation.

ΔE = hbar/(2Δt) = 5.25x10^-32

b. Use ΔE=hΔf to find the frequency.

Δf = 79.6 s^-1

if I were to plug this into ΔλΔf=c, it results in a very large Δλ which is unphysical.

Δλ = ?
 
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that is the right method. the result is not a wavelength, but an uncertainty in the wavelength, and it should be a fraction of 500nm
 
The resulting uncertainty is in the hundreds of meters though =(
 
While it's true that ##\lambda f = c##, it doesn't follow that ##\Delta \lambda \Delta f=c##.
 
work out the energy associated with the transition, then work out the ratio of the uncertainty of the energy and the energy of the transition. the energy is related to the wavelength of a particle through the dispersion relation. assume a non relativistic electron's dispersion relation, and work out the wavelength uncertainty from there.
 

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