What is the unknown charge if the net electrostatic force on particle 1 is zero?

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The discussion centers on determining the unknown charge q that results in a net electrostatic force of zero on particle 1 in a square configuration of charged particles. The known charges are q1 and q4, both equal to 1.06 × 10-15 C, while q2 and q3 are the unknown charges. The net force acting on particle 1 from particle 4 is calculated to be 8.45E-18 N, and the X component of the force from particle 2 is negative 6.00E-18 N. An initial calculation for q yielded 7.49E-16 C, but this was incorrect due to using the wrong distance in the formula. The correct approach involves ensuring the proper distance is used to achieve the correct charge value for q.
Monkey_Man08
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1. The problem statement: In the figure four particles form a square with edge length a = 2.44 × 10-2 m. The charges are q1 = q4 = 1.06 × 10-15 C and q2 = q3 = q. What is q if the net electrostatic force on particle 1 is zero?
All variables and given/known data: The given variable are in the statement, but I have calculated and checked some other important variables.
  • Net force acting on particle 1 by particle 4 is 8.45E-18 N.
  • The X component of the force acting on particle 1 by particle 2 is negative 6.00E-18 N.
  • Distance from particle 1 to particle 4 is 0.034507 m.

Homework Equations

: Coulomb Force:
11bfec934e963740d4bed02c2062a4e7.png
, where k = 8.99E9[/B]

The Attempt at a Solution


Since I'm using the above equation to solve for q2, I used algebra to set it up as q2 = (F)(r2) / (k)(q1). Once I plugged the numbers I have (6.00E-18)(1.19E-3) / (8.99E9)(1.06E-15). Once I plug all that in the calculator, I'm left with 7.49E-16 C. But supposedly that is the wrong answer. I've checked my math enough to know all the information above "The attempt at a solution" portion is correct, so the problem must lie within this final step... I think.
 

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Note that when inputting my final answer I put in negative 7.49E-16 C, because in order for particle 2 and 3 to counteract the forces of particle 4, they must have a negative charge.
 
I was using the wrong distance for r in my final calculation. All is solved.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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