- #1

SilentBlade91

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## Homework Statement

A 27.1-kg block (m1) is on a horizontal surface,

connected to a 5.7-kg block (m2) by a massless string as

shown in the Figure. The pulley is massless and friction-

less. A force of 228.9 N acts on m1 at an angle of 33.5◦.

The coefficient of kinetic friction between m1 and the sur-

face is 0.201. Determine the upward acceleration of m2.

(m2 is dangling off the ledge by the pully connected to m1)

## Homework Equations

Fg=mg

F=ma

Fk=uk(Fn)

## The Attempt at a Solution

I drew all the forces, m1 would have Fg=265.58 going down and Fy=126.338 going up because of the angle it is pulled at. So then I figured Fn would be 265.58-126.338=139.242. And Fx=190.876. And the Fk=.201(139.242)=27.9876. Then m2 would have an Fg=55.86.

I found net force= Fx-Fk-Fgm2=107.028. Then I used F=ma to try and find upward accel of m2. I figured since the force is being applied to m1 and it is connected to m2 I would use the combined mass of both of them and do 107.028=(5.7+27.1)(a) and a came out to be 3.26305m/s^2 but it turns out that was wrong. Can anybody help me find the real answer?